怎么输出跳转不对的呢

[xinqq163]

$gofrom=$_SERVER['HTTP_REFERER'];
//echo $gofrom;
//exit;
if($jx_yzm_from_post!= $jx_yzm_from_cookie){
echo '<script language="JavaScript">alert("验证码错误!");window.location.href='"+$gofrom+"';</script>';
exit;
}

gofrom 这样跳写错哪里了呢

[life169]

echo '<script language="JavaScript">alert("验证码错误!");window.location.href='"+$gofrom+"';</script>';
改成：

echo '<script language="JavaScript">alert("验证码错误!");window.location.href="'.$gofrom.'";</script>';

[skyaspnet]

[Quote=引用楼主 liaohongchu 的回复:]
$gofrom=$_SERVER['HTTP_REFERER'];
//echo $gofrom;
//exit;
if($jx_yzm_from_post!= $jx_yzm_from_cookie){
echo '<script language="JavaScript">alert("验证码错误!");window.location.href='"+$gofrom+"';</scri……
[/Quote]

代码修改如下即可：

$gofrom=$_SERVER['HTTP_REFERER'];
//echo $gofrom;
//exit;
if($jx_yzm_from_post!= $jx_yzm_from_cookie){
echo '<script language="JavaScript">alert("验证码错误!");window.location.href="'.$gofrom.'.";</script>';
exit;
}

[brilliant_fgh]

$gofrom=$_SERVER['HTTP_REFERER'];

if($jx_yzm_from_post!= $jx_yzm_from_cookie)
{

echo '<script>alert("验证码错误!");location.href='".$gofrom."';</script>';
exit;

}

[用户昵称不能为空]

[Quote=引用 3 楼 dhc_1229 的回复:]

href='"+$gofrom+"'
改成href='".$gofrom."'
[/Quote]

[dhc_1229]

href='"+$gofrom+"'
改成href='".$gofrom."'

[zhanghaoranjn]

[Quote=引用 3 楼 dhc_1229 的回复:]
href='"+$gofrom+"'
改成href='".$gofrom."'
[/Quote]
顶。。。。。。。。。。。。。。。。