一道程序设计题，望高手相助！

[zcxwlh]

设名为staff的包中包含两个类，Employee和Manager，其中Manager为Employee的子类，定义如下：

class Employee {
String name; //雇员姓名
int age; //年龄
char grade; //业绩评等，从高到低为A,B,C,D四等。
}

class Manager extends Employee {
String department; //Manager所管辖部门
Employee[] subm; //下属雇员
}

请在包中定义一个名为TopManager的类，在该类中定义若干Employee和Manager的样本值，然后写一方法，找出所有Manager中其下属雇员平均业绩评等最高的Manager姓名。

[star95hmz]

public class Employee {
	String name; //雇员姓名
	int age; //年龄 
	char grade; //业绩评等，从高到低为A,B,C,D四等。
	public Employee(String name,int age,char grade){
		this.name=name;
		this.age=age;
		this.grade=grade;
	}
	}

public class Manager extends Employee {
	public Manager(String name, int age, char grade,String department,Employee[] subm) {
		super(name,age,grade);
		this.department=department;
		this.subm=subm;
		
	}
	String department; //Manager所管辖部门
	Employee[] subm; //下属雇员
	}

public class TopManager {
	Employee Employee1=new Employee("zhangsan1", 21, 'A');
	Employee Employee2=new Employee("zhangsan2", 22, 'B');
	Employee Employee3=new Employee("zhangsan3", 23, 'C');
	Employee Employee4=new Employee("zhangsan4", 24, 'D');
	Employee Employee5=new Employee("zhangsan5", 25, 'A');
	Employee Employee6=new Employee("zhangsan6", 26, 'B');
	Employee Employee7=new Employee("zhangsan7", 27, 'C');
	Employee Employee8=new Employee("zhangsan8", 28, 'D');
	Employee Employee9=new Employee("zhangsan9", 29, 'A');
	Employee[] subm1={Employee1,Employee2,Employee3,Employee4};
	Employee[] subm2={Employee5,Employee6,Employee7,Employee8,Employee9};
	Manager Manager1=new Manager("Manager1", 31, 'A', "sale", subm1);
	Manager Manager2=new Manager("Manager2", 32, 'B', "produce", subm2);
	
	public static void main(String[] args) {
		TopManager TopManager1=new TopManager();
		Manager ManagerTop=TopManager1.find();
		System.out.println("下属雇员平均业绩评等最高的Manager是:"+ManagerTop.department+"的"+ManagerTop.name);
	}
	/*
	 * find方法是找出其下属雇员平均业绩评等最高的Manager
	 * */
	public Manager find(){
		float avg1,avg2;
		int sum1=0,sum2=0;
		for(int i=0;i<subm1.length;i++){
			sum1=sum1+subm1[i].grade;
		}
		avg1=(float)sum1/(float)subm1.length;
		for(int i=0;i<subm2.length;i++){
			sum2=sum2+subm2[i].grade;
		}
		avg2=(float)sum2/(float)subm2.length;
		//由于本方法是用的是字符型的转为整型的然后求的平均值，所以小的值结果等级高
		if(avg1<avg2){
			return Manager1;
		}
		if(avg1>=avg2){
			return Manager2;
		}
		return Manager1;
	}
}

[peggy0135]

樓上
請教一下
它的grade是char的型態耶
為什麼可以當float來加????

[peggy0135]

正在思考
請教大大要怎麼PO
java的souce code

[mucrea]

这个是设计模式里面的一个经典案例，应该是访问者模式。你可以细细查查！

[peggy0135]

public class Employee
{
	protected String name;
	private int age;
	protected char grade;
	
	public Employee( String n, int a, char g )
	{
		name = n;
		age = a;
		grade = g;
	}
	
	public String getName()
	{
		return name;
	}
	
	public int getAge()
	{
		return age;
	}
	
	public char getGrade()
	{
		return grade;
	}
	
	public void printInfo()
	{
		System.out.println( "name: " + getName() );
		System.out.println( "age: " + getAge() );
		System.out.println( "grade: " + getGrade() );
	}
}

public class Manager extends Employee
{
	private String department;
	private double average;
	private Employee[] subm = new Employee[10];
	private int pos;
	
	public Manager( String name, int age, char grade, String department )
	{
		super( name, age, grade );
		this.department = department;
		pos = 0;
	}
	
	public void addEmployee( Employee workman )
	{
		subm[ pos ] = workman;
		pos++;
	}
	public void printManager()
	{
		System.out.println( "name: " + name );
		System.out.println( "department: " + department );
		System.out.println( "grade: " + grade );
	}
	public String getName()
	{
		return name;
	}
	
	public void printInfo()
	{
		System.out.println( "department: " + department );
		System.out.println( "manager: " + name );
		System.out.println( "work men: " );
		for( int i = 0; i < subm.length; i++ )
		{
			subm[i].printInfo();
			System.out.println();
		}
		
		System.out.println( "-----------" );
	}
	
	public void countAverage()
	{
		int sum = 0;
		
		for( int i = 0; i < subm.length; i++ )
		{
			sum += subm[i].getGrade();
		}
		
		average = sum / subm.length;
	}
	
	public void sortGrade()
	{
		boolean change = true;
		while( change )
		{
			change = false;
			
			for( int i = 0; i < subm.length-1; i++ )
			{
				int g1, g2 = 0;
				g1 = subm[i].getGrade();
				g2 = subm[i+1].getGrade();
				if( g1 > g2 )
				{
					Employee temp = subm[i+1];
					subm[i+1] = subm[i];
					subm[i] = temp;
					change = true;
				}
			}
		}
	}
	
	public char getGrade()
	{
		int theAverage = (int) average;
		switch( theAverage )
		{
			case 4:
			grade = 'A';
			break;
			
			case 3:
			grade = 'B';
			break;
			
			case 2:
			grade = 'B';
			break;
			
			case 1:
			grade = 'B';
			break;
		}
		
		return grade;
	}
}

public class TopManager
{
	private String name;
	private int pos;
	private Manager[] subManager = new Manager[3];
	
	public TopManager( String name )
	{
		this.name = name;
	}
	
	public void addManager( Manager manager )
	{
		subManager[pos] = manager;
		pos++;
	}
	
	public void sortGrade()
	{
		boolean change = true;
		while( change )
		{
			change = false;
			
			for( int i = 0; i < subManager.length-1; i++ )
			{
				int g1, g2 = 0;
				g1 = subManager[i].getGrade();
				g2 = subManager[i+1].getGrade();
				if( g1 > g2 )
				{
					Manager temp = subManager[i+1];
					subManager[i+1] = subManager[i];
					subManager[i] = temp;
					change = true;
				}
			}
		}
	}
	
	public void printInfo()
	{
		System.out.println( "generl manager: " + name );
		for( int i = 0; i < subManager.length; i++ )
		{
			subManager[i].printInfo();
			System.out.println( "-----------" );
		}
		System.out.println();
	}
	
	public void showBest()
	{
		subManager[subManager.length-1].printManager();
	}
}

public class Company
{
	public static void main( String[] args )
	{
		TopManager topmanager = new TopManager( "Lee" );
		
		Manager manager1 = new Manager( "Iee", 35, 'A', "produce");
		Manager manager2 = new Manager( "Jee", 36, 'A', "sale");
		Manager manager3 = new Manager( "kee", 39, 'A', "service");
		
		topmanager.addManager( manager1 );
		topmanager.addManager( manager2 );
		topmanager.addManager( manager3 );
		
		for( int i = 0; i < 10; i++ )
		{
			manager1.addEmployee( new Employee( "wang", 21+i, 'A' ) );
		}
		
		for( int i = 0; i < 10; i++ )
		{
			manager2.addEmployee( new Employee( "Chang", 19+i, 'B' ) );
		}
		
		for( int i = 0; i < 10; i++ )
		{
			manager3.addEmployee( new Employee( "Liue", 21+i, 'A' ) );
		}
		
		manager1.countAverage();
		manager1.sortGrade();
		manager2.countAverage();
		manager2.sortGrade();
		manager3.countAverage();
		manager3.sortGrade();
		
		topmanager.sortGrade();
		topmanager.printInfo();
		topmanager.showBest();
	}
}

大大要的話可以再加一些讓使用者操作的功能