读取txt文件中的负数？？？

[erlingmusan]

U.txt中的数据
-721.687179 -815.804502 -811.202694 -789.820228 -819.852144 -892.327928 -855.463031 -896.633812 -883.067909 -854.481898 -827.922019 -881.006647 -834.705544 -823.172092 -806.361069 -817.773490 -838.073045 -839.921275 -928.714609 -837.331740 -816.831521
-20.263213 -3.191537 38.048945 34.034564 38.551518 -9.860831 48.968289 47.625681 37.903990 67.662095 -39.756499 -32.747018 -61.186375 -12.614137

怎么把U.txt中的数据读到一个二维数组中，里面有负数，不知道怎么读？

[thegreatone]

直接用读入double类型的变量中就行了

[thegreatone]

#include <iostream>
#include <fstream>
#include <cstdlib>
#include <string>

using namespace std;

int main()
{
	ifstream infile;
	infile.open("U.txt",ios::in);
	if(!infile) 
	{
		cout<<"fail to open the file source.txt"<<endl;
		exit(1);
	}
	double data;
	while(infile>>data)
	{
		cout<<data<<" ";
	}
	infile.close();
	
	return 0; 	
}

[hongwenjun]

#include <iostream>
#include <vector>
#include <fstream>
#include <algorithm>

using namespace std;

int main()
{
    double x;
    vector<double> shuzi;
    vector<double>::iterator iter;
    fstream fin;
    fin.open("a.txt");
    if(!fin) {
        cout<<"不能打开文件"<<endl;
        return -1;
    }

    while(fin >> x) {
        shuzi.push_back(x);
    }

    sort(shuzi.begin(),shuzi.end());
    for (iter=shuzi.begin(); iter!=shuzi.end() ; iter++ )
        cout << *iter << endl;
    fin.close();

    cout <<"总共数字"<< shuzi.size();
    return 0;
}

[dingshaofengbinbin]

不就是字符转换吗？？

[qq120848369]

C语言方法fscanf("%lf"),C++方法如上。

[pmars]

读取负数和正数没有什么区别，写一样的程序，让编译器去工作吧……

[delphiwcdj]

[Quote=引用 5 楼 qq120848369 的回复:]

C语言方法fscanf("%lf"),C++方法如上。
[/Quote]
++