来个正则高手

[验证码识别]

input:
----------------------
u="3" ach="67" classId="5"
u="4" ach="251" classId="0"
-------------------------

我要得到如下结果
-----------------------------
be:67/5
be:251/0

用下面形式的代码
Regex re = new Regex(pattern);
MatchCollection myMatchs = re.Matches(input);


能否实现?
正则表达式pattern怎么写?

[PandaIT]

//写得太烂了
string inputStr = "u=\"3\" ach=\"67\" classId=\"5\"  u=\"4\" ach=\"251\" classId=\"0\"";

            Regex re = new Regex("(?i).*?ach=\"(?<ach>.*?)\"\\sclassId=\"(?<classId>.*?)\"");
            MatchCollection myMatchs = re.Matches(inputStr);
            string str = "";
            foreach (Match item in myMatchs)
            {
                str += "de:" + item.Groups["ach"].Value + "/" + item.Groups["classId"].Value;
            }
            MessageBox.Show(str);

[验证码识别]

[Quote=引用 13 楼 wuyazhe 的回复:]
可以

C# code
string result = Regex.Replace(yourStr,@"(?m:^).+?\bach=\x22(\d+).+classId=\x22(\d+)\S+","be:$1/$2");
[/Quote]

用这个
Regex re = new Regex(pattern);
re.Match(input);

有没有可能匹配的结果 match.value 就是替换后的?
有这样的pattern没有?

[xiaoqiu1234]

[Quote=引用 1 楼 zhoukang0916 的回复:]
C# code

//写得太烂了
string inputStr = "u=\"3\" ach=\"67\" classId=\"5\" u=\"4\" ach=\"251\" classId=\"0\"";

Regex re = new Regex("(?i).*?ach=\"(?<ach>.*?)\"\\sclassId=\"(?<classId>.*?)……
[/Quote]

[-过客-]

try...

string test = @"u=""3"" ach=""67"" classId=""5""  
u=""4"" ach=""251"" classId=""0""";
Regex reg = new Regex(@"(?i)ach=""([^""]*)""\s+classid=""([^""]*)""");
MatchCollection mc = reg.Matches(test);
foreach (Match m in mc)
{
    richTextBox2.Text += "be:" + m.Groups[1].Value + "/" + m.Groups[2].Value + "\n";
}

[兔子-顾问]

string test = @"u=""3"" ach=""67"" classId=""5"";
foreach(Match m in Regex.Matches(test,@"(?m:^).+?ach=\x22(\d+).+?classId=\x22(\d+)"))
{
    string result = "be:" + m.Groups[1].Value + "/" + m.Groups[2].Value + "\n";
    Console.WriteLine(result);
}

[兔子-顾问]

string test = @"u=""3"" ach=""67"" classId=""5""";
foreach(Match m in Regex.Matches(test,@"(?m:^).+?ach=\x22(\d+).+?classId=\x22(\d+)"))
{
    string result = "be:" + m.Groups[1].Value + "/" + m.Groups[2].Value + "\n";
    Console.WriteLine(result);
}

[Joop_Song]

楼上的几位都是大牛啊！领教了，mark、、

[yalan]

[Quote=引用 5 楼 wuyazhe 的回复:]
C# code
string test = @"u=""3"" ach=""67"" classId=""5""";
foreach(Match m in Regex.Matches(test,@"(?m:^).+?ach=\x22(\d+).+?classId=\x22(\d+)"))
{
string result = "be:" + m.Groups[1].Value + "……
[/Quote]

恩恩，这个好~~~~~~

[h2ero]

[Quote=引用 8 楼 yalan 的回复:]

引用 5 楼 wuyazhe 的回复:
C# code
string test = @"u=""3"" ach=""67"" classId=""5""";
foreach(Match m in Regex.Matches(test,@"(?m:^).+?ach=\x22(\d+).+?classId=\x22(\d+)"))
{
string result = "be:" + m.G……
[/Quote]
确实好！

[h2ero]

我写的烂代码，

string str = "u=\"3\" ach=\"67\" classId=\"5\" u=\"4\" ach=\"251\" classId=\"0\"";
            Regex re = new Regex("(.*?)ach=\"(.*?)\"(.*?)classId=\"(.*?)\"(.*?)");
            MatchCollection result = re.Matches(str);
            foreach (Match item in result)
            {
                
                Console.WriteLine("be:"+item.Groups[2]+"/"+item.Groups[4]);
            }
            Console.ReadLine();

[验证码识别]

[Quote=引用 4 楼 wuyazhe 的回复:]
C# code
string test = @"u=""3"" ach=""67"" classId=""5"";
foreach(Match m in Regex.Matches(test,@"(?m:^).+?ach=\x22(\d+).+?classId=\x22(\d+)"))
{
string result = "be:" + m.Groups[1].Value + "/……
[/Quote]

没有办法在正则表达式中直接替换为 be: ?

[兔子-顾问]

可以

string result = Regex.Replace(yourStr,@"(?m:^).+?\bach=\x22(\d+).+classId=\x22(\d+)\S+","be:$1/$2");