求救—一个关于switch的问题。

[petpwiuta]

#include "stdio.h"
void main()
{

double profit,bonus;
int option;
scanf("%f",&profit);
if(profit<100000)
option=1;
else if(profit>=100000&&profit<200000)
option=2;
else if(profit>=200000&&profit<400000)
option=3;
else if(profit>=400000&&profit<600000)
option=4;
else if(profit>=600000&&profit<1000000)
option=5;
else if(profit>=1000000)
option=6;
switch(option)
{
case 1: bonus=100000*0.1; break;
case 2: bonus=100000*0.1+(profit-100000)*0.75; break;
case 3: bonus=100000*0.1+(profit-100000)*0.75+(profit-200000)*0.05; break;
case 4: bonus=100000*0.1+(profit-100000)*0.75+(profit-200000)*0.05+(profit-400000)*0.03; break;
case 5: bonus=100000*0.1+(profit-100000)*0.75+(profit-200000)*0.05+(profit-400000)*0.03+(profit-600000)*0.15; break;
case 6: bonus=100000*0.1+(profit-100000)*0.75+(profit-200000)*0.05+(profit-400000)*0.03+(profit-600000)*0.15+(profit-1000000)*0.01); break;

}
printf("bonus is %f",bonus);
}
大虾们出出主意，这个代码在VC6里面老是过不了。

[chentian0926]

]#include "stdio.h"
void main()
{

  double profit,bonus;
  int option;
  scanf("%f",&profit);
  if(profit<100000)
  option=1;
  else if(profit>=100000&&profit<200000)
  option=2;
  else if(profit>=200000&&profit<400000)
  option=3;
  else if(profit>=400000&&profit<600000)
  option=4;
  else if(profit>=600000&&profit<1000000)
  option=5;
  else if(profit>=1000000)
  option=6;
  switch(option)
  {
  case 1: bonus=100000*0.1; break;
  case 2: bonus=100000*0.1+(profit-100000)*0.75; break;  
  case 3: bonus=100000*0.1+(profit-100000)*0.75+(profit-200000)*0.05; break;
  case 4: bonus=100000*0.1+(profit-100000)*0.75+(profit-200000)*0.05+(profit-400000)*0.03; break;
  case 5: bonus=100000*0.1+(profit-100000)*0.75+(profit-200000)*0.05+(profit-400000)*0.03+(profit-600000)*0.15; break;
  case 6: bonus=100000*0.1+(profit-100000)*0.75+(profit-200000)*0.05+(profit-400000)*0.03+(profit-600000)*0.15+(profit-1000000)*0.01); break;
  
  }
  printf("bonus is %f",bonus);
}

多了个东东啥

[chentian0926]

case 6: bonus=100000*0.1+(profit-100000)*0.75+(profit-200000)*0.05+(profit-400000)*0.03+(profit-600000)*0.15+(profit-1000000)*0.01); break;


标记的地方多了

[xingxingc2]

倒数第三行，你；break前多了括号） 括号要正确匹配

[人尽其材]

初学者。。。

[lan243675044]

在case 6 的那条语句末尾break前多了一个 ) "括号"。

[菩提树下写代码]

一个很明显的错误

[petpwiuta]

呵呵，编译通过了，但还有逻辑错误，不过先谢谢你们了。