？？？如何用正则从字符串中提取float型数字？？？

[大黄鸭在发光]

string str = “141800Z --- NEAR 13.5N 137.7E”；
最后能得到数组，数组里放｛141800，13.5，137.7｝
谢谢大家！！

[ddyouyue]

(?:\\-)?\\d{1,}(?:\\.\\d{1,})?

[zqfddqr]

public class s {

    public static void main(String[] args) {
        String s = "141800Z --- NEAR 13.5N 137.7E";
        double[] d = new double[3];
        int i = 0;
        for (String ss : s.split("[^0-9.]")) {
            if (!ss.equals("")) {
                System.out.println(ss);
                d[i++]=Double.valueOf(ss);
            }
        }
        for(double dd:d)
            System.out.println(dd);
    }
}

141800
13.5
137.7
141800.0
13.5
137.7

[eXeSP]

		String str = "141800Z --- NEAR 13.5N 137.7E";
		String [] ss = str.split("([-a-zA-Z]\\s*)++");

141800
13.5
137.7

[caibird1024]

String[] strs = str.split("[a-zA-Z\\- ]");
for(int i=0;i<strs.length;i++){
if(!"".equals(strs[i])){
System.out.println(strs[i]);
}
}

[看着奢扣]

split("[^0-9.]")
把数字和小数点以外的东西作为分隔符，得到数字

[看着奢扣]

import java.util.regex.Matcher;
import java.util.regex.Pattern;
import java.util.Collection;
import java.util.ArrayList;

//正则表达式测试
public class RegularExpressionTest {
	public static void main(String[] args) {
		String waitToMatch1 = "141800Z --- NEAR 13.5N 137.7E";
		Pattern pattern = Pattern.compile("\\d+.\\d+"); 
		Matcher matcher = pattern.matcher(waitToMatch1);
		printMatcher(matcher);
	}
	private static void printMatcher(Matcher matcher) {
		ArrayList aClass = new ArrayList();
		while (matcher.find()) {
			//System.out.println(matcher.group());
			aClass.add(matcher.group());
		}
		System.out.println(aClass);
	}
}

打印
[141800, 13.5, 137.7]