出现异常？？？？

234234orz 2011-03-30 06:28:50

import java.io.*;
import java.lang.*;
public class ConvertId {
public static void main(String args[]){
String IdNumber=""; int index;
System.out.println("please input ID number: ");

try{
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
IdNumber = in.readLine();
index = Integer.parseInt(IdNumber);
}catch(IOException e) {}
catch(NumberFormatException e) {e.printStackTrace();}

if(IdNumber.length()==18) {
int s1 =Integer.parseInt(IdNumber.substring(6,10));
int s2 =Integer.parseInt(IdNumber.substring(10,12));
int s3 =Integer.parseInt(IdNumber.substring(12,14));
System.out.println("---------------------------------------------");
System.out.println("the birthday is "+s1+" year "+s2+" month "+s3+" day ");
int age =2011-s1;

System.out.println("the age is "+age);
if((int)IdNumber.charAt(17)%2==0)
System.out.println("the people ia a man");
else System.out.println("the people is a woman:");
}

if(IdNumber.length()==15){
String code;
int num = 0;
StringBuffer IdNumber1 = new StringBuffer(IdNumber);
IdNumber1.insert(6,"19");
//IdNumber = IdNumber.substring(0,5)+"19"+IdNumber.substring(6,14);
for(int i=17; i>=0; i--)
num+=(int)Math.pow(2,i-1)*(Integer.parseInt(IdNumber1.substring(i)));
num%=11;
switch(num) {
case 0: code = "1"; break;
case 1: code = "0"; break;
case 2: code = "X"; break;
default: code = 12-num+" "; break;
}
IdNumber1 =IdNumber1.append(code);
System.out.println(IdNumber1);
}
}
}

...全文

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234234orz 2011-03-30

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恩啊哈 Int ->double

JavaMan 2011-03-30

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如果是解析身份证的话，不需要转换为Int啊！

wolf863292 2011-03-30

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身份证用String吧，难道你不知道身份证中有可能出现“X”吗？

lost_guy_in_scut 2011-03-30

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用Double吧~

234234orz 2011-03-30

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类型我改了但是还是报异常
Exception in thread "main" java.lang.NumberFormatException: For input string:

at java.lang.NumberFormatException.forInputString(NumberFormatExceptio
java:48)
at java.lang.Integer.parseInt(Integer.java:467)
at java.lang.Integer.parseInt(Integer.java:496)
at Test.main(Test.java:48)
求一点意见新手~~~~~~~~

lost_guy_in_scut 2011-03-30

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写错了 int的最大值（2^32-1）
你的需求要15位和18位~~
还是3楼说的对~呵呵~

234234orz 2011-03-30

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Exception in thread "main" java.lang.NumberFormatException: For input string:

at java.lang.NumberFormatException.forInputString(NumberFormatExceptio
java:48)
at java.lang.Integer.parseInt(Integer.java:467)
at java.lang.Integer.parseInt(Integer.java:496)
at Test.main(Test.java:48)

234234orz 2011-03-30

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改了但是还是有异常

lost_guy_in_scut 2011-03-30

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	try{

	BufferedReader in = new BufferedReader(new InputStreamReader(System.in));

	  IdNumber = in.readLine();

//	  System.out.println(IdNumber);

	  //因为你读取到的一行数据后面是有空格的

	  //parseInt 无法将空格转化为数字

	  index = Integer.parseInt(IdNumber.trim());

	  }catch(IOException e) {

		  e.printStackTrace();

		 System.out.println("exceiptin is "+e);

	  }

还有就是你的index明明没有用到~你定义它干嘛呢？

234234orz 2011-03-30

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magong 2011-03-30

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[Quote=引用楼主 liaq325 的回复:]
String IdNumber=""; int index;

index = Integer.parseInt(IdNumber);

[/Quote]
18位身份证号码对于int太大了，用long吧。上面两行代码这么改
String IdNumber=""; long index;
和
index = Long.parseLong(IdNumber);