拆列问题

xuam 2011-03-31 11:28:17
表table

数据:
col
A
B/C
D/E/F
G/H


结果要求:
A
B
C
D
E
F
G
H
咋拆? sql2000
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叶子 2011-03-31
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declare @table table (col varchar(5))
insert into @table
select 'A' union all
select 'B/C' union all
select 'D/E/F' union all
select 'G/H'

SELECT col = SUBSTRING(a.col, b.number,
CHARINDEX('/', a.col + '/', b.number) - b.number)
FROM @table a
JOIN master..spt_values b ON b.type = 'p'
AND b.number BETWEEN 1 AND LEN(a.col)
WHERE SUBSTRING('/' + a.col, b.number, 1) = '/'
/*
col
-----
A
B
C
D
E
F
G
H
*/
快溜 2011-03-31
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create table tb(val varchar(10))
insert into tb
select 'A' union all
select 'B/C' union all
select 'D/F/E'
go
select b.id from tb a,(select 'A' as id union select 'B' union select 'C' union select 'D'
union select 'E' union select 'F') b
where CHARindex(b.id+'/',a.val+'/')>0
/*
id
----
A
B
C
D
E
F
--小F-- 2011-03-31
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select 
col = substring(a.col , b.number , charindex('/' , a.col + '/' , b.number) - b.number)
from
tb a
join master..spt_values b
on
b.type='p' and b.number between 1 and len(a.col)
where
substring('/' + a.col , b.number , 1) = '/'
AcHerat 元老 2011-03-31
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create table tb(val varchar(10))
insert into tb
select 'A' union all
select 'B/C' union all
select 'D/F/E'
go

select val = substring(a.val , b.number , charindex('/' , a.val + '/' , b.number) - b.number)
from tb a join master..spt_values b
on b.type='p' and b.number between 1 and len(a.val)
where substring('/' + a.val , b.number , 1) = '/'

drop table tb

/*
val
----------
A
B
C
D
F
E

(6 行受影响)

dawugui 2011-03-31
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参考:
/*
标题:简单数据拆分(version 2.0)
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2010-05-07
地点:重庆航天职业学院
描述:

有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
*/

--1. 旧的解决方法(sql server 2000)

create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go

--方法1.使用临时表完成
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b

SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','

DROP TABLE #

--方法2.如果数据量小,可不使用临时表
select a.id , value = substring(a.value , b.number , charindex(',' , a.value + ',' , b.number) - b.number)
from tb a join master..spt_values b
on b.type='p' and b.number between 1 and len(a.value)
where substring(',' + a.value , b.number , 1) = ','

--2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go

--方法1.使用xml完成
SELECT A.id, B.value FROM
(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
) A OUTER APPLY
(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
) B

--方法2.使用CTE完成
;with tt as
(select id,[value]=cast(left([value],charindex(',',[value]+',')-1) as nvarchar(100)),Split=cast(stuff([value]+',',1,charindex(',',[value]+','),'') as nvarchar(100)) from tb
union all
select id,[value]=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from tt where split>''
)
select id,[value] from tt order by id option (MAXRECURSION 0)


DROP TABLE tb

/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc

(5 行受影响)
*/



喜-喜 2011-03-31
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都是神...

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