一个基本的sql查询

aoteman_prc 2011-04-02 09:43:10
小弟现在有一个小问题,想要一个sql,
ID Title Type
1 AAA 1
2 AA1 2
3 AA2 3
4 AA3 1
5 AA4 2
6 AA5 3
7 AA6 1
8 AA7 2
9 AA8 3
10 AA9 1
11 A10 2
12 A12 3
13 A13 1
14 A14 2
15 A15 3

想用一句sql取得如下的结果
Title Type
AAA 1
AA3 1
AA1 2
AA4 2
AA5 3
AA8 3
就是根据type取每个Type最新的两条记录,求各位大侠们指教
...全文
71 6 打赏 收藏 转发到动态 举报
写回复
用AI写文章
6 条回复
切换为时间正序
请发表友善的回复…
发表回复
--小F-- 2011-04-02
  • 打赏
  • 举报
回复
select
*
from
tb a
cross apply
(select top 2 * from tb where type=a.type order by type )b
--小F-- 2011-04-02
  • 打赏
  • 举报
回复
---------------------------------
-- Author: liangCK 小梁
-- Title : 查每个分组前N条记录
-- Date : 2008-11-13 17:19:23
---------------------------------

--> 生成测试数据: #T
IF OBJECT_ID('tempdb.dbo.#T') IS NOT NULL DROP TABLE #T
CREATE TABLE #T (ID VARCHAR(3),GID INT,Author VARCHAR(29),Title VARCHAR(39),Date DATETIME)
INSERT INTO #T
SELECT '001',1,'邹建','深入浅出SQLServer2005开发管理与应用实例','2008-05-10' UNION ALL
SELECT '002',1,'胡百敬','SQLServer2005性能调校','2008-03-22' UNION ALL
SELECT '003',1,'格罗夫Groff.J.R.','SQL完全手册','2009-07-01' UNION ALL
SELECT '004',1,'KalenDelaney','SQLServer2005技术内幕存储引擎','2008-08-01' UNION ALL
SELECT '005',2,'Alex.Kriegel.Boris.M.Trukhnov','SQL宝典','2007-10-05' UNION ALL
SELECT '006',2,'飞思科技产品研发中心','SQLServer2000高级管理与开发','2007-09-10' UNION ALL
SELECT '007',2,'胡百敬','SQLServer2005数据库开发详解','2008-06-15' UNION ALL
SELECT '008',3,'陈浩奎','SQLServer2000存储过程与XML编程','2005-09-01' UNION ALL
SELECT '009',3,'赵松涛','SQLServer2005系统管理实录','2008-10-01' UNION ALL
SELECT '010',3,'黄占涛','SQL技术手册','2006-01-01'

--SQL查询如下:

--按GID分组,查每个分组中Date最新的前2条记录


--1.字段ID唯一时:
SELECT * FROM #T AS T WHERE ID IN(SELECT TOP 2 ID FROM #T WHERE GID=T.GID ORDER BY Date DESC)

--2.如果ID不唯一时:
SELECT * FROM #T AS T WHERE 2>(SELECT COUNT(*) FROM #T WHERE GID=T.GID AND Date>T.Date)

--SQL Server 2005 使用新方法

--3.使用ROW_NUMBER()进行排位分组
SELECT ID,GID,Author,Title,Date
FROM
(
SELECT rid=ROW_NUMBER() OVER(PARTITION BY GID ORDER BY Date DESC),*
FROM #T
) AS T
WHERE rid<=2

--4.使用APPLY
SELECT DISTINCT b.*
FROM #T AS a
CROSS APPLY
(
SELECT TOP(2) * FROM #T WHERE a.GID=GID ORDER BY Date DESC
) AS b


--结果
/*

ID GID Author Title Date
---- ----------- ----------------------------- --------------------------------------- -----------------------
003 1 格罗夫Groff.J.R. SQL完全手册 2009-07-01 00:00:00.000
004 1 KalenDelaney SQLServer2005技术内幕存储引擎 2008-08-01 00:00:00.000
005 2 Alex.Kriegel.Boris.M.Trukhnov SQL宝典 2007-10-05 00:00:00.000
007 2 胡百敬 SQLServer2005数据库开发详解 2008-06-15 00:00:00.000
009 3 赵松涛 SQLServer2005系统管理实录 2008-10-01 00:00:00.000
010 3 黄占涛 SQL技术手册 2006-01-01 00:00:00.000

(6 行受影响)
*/
天-笑 2011-04-02
  • 打赏
  • 举报
回复


declare @t table (id int , title varchar(8),type int)
insert into @t
select 1,'AAA',1 union all
select 2,'AA1',2 union all
select 3,'AA2',3 union all
select 4,'AA3',1 union all
select 5,'AA4',2 union all
select 6,'AA5',3 union all
select 7,'AA6',1 union all
select 8,'AA7',2 union all
select 9,'AA8',3 union all
select 10,'AA9',1 union all
select 11,'A10',2 union all
select 12,'A11',3 union all
select 13,'A12',1 union all
select 14,'A13',2 union all
select 15,'A14',3

;with t as (
select RANK() over (PARTITION by type order by type ,id) as no ,* from @t )

select * from t where no <=2

----------------------

1 1 AAA 1
2 4 AA3 1
1 2 AA1 2
2 5 AA4 2
1 3 AA2 3
2 6 AA5 3


chuanzhang5687 2011-04-02
  • 打赏
  • 举报
回复
select t.* from tb t where id in 
(select top 2 id from tb where Type = t.Type order by id)
order by t.type , t.id
dawugui 2011-04-02
  • 打赏
  • 举报
回复
create table tb(ID int,Title varchar(10),Type int)
insert into tb values(1 ,'AAA', 1)
insert into tb values(2 ,'AA1', 2)
insert into tb values(3 ,'AA2', 3)
insert into tb values(4 ,'AA3', 1)
insert into tb values(5 ,'AA4', 2)
insert into tb values(6 ,'AA5', 3)
insert into tb values(7 ,'AA6', 1)
insert into tb values(8 ,'AA7', 2)
insert into tb values(9 ,'AA8', 3)
insert into tb values(10 ,'AA9', 1)
insert into tb values(11 ,'A10', 2)
insert into tb values(12 ,'A12', 3)
insert into tb values(13 ,'A13', 1)
insert into tb values(14 ,'A14', 2)
insert into tb values(15 ,'A15', 3)
go

select t.* from tb t where id in (select top 2 id from tb where Type = t.Type order by id) order by t.type , t.id

drop table tb

/*
ID Title Type
----------- ---------- -----------
1 AAA 1
4 AA3 1
2 AA1 2
5 AA4 2
3 AA2 3
6 AA5 3

(所影响的行数为 6 行)
*/
dawugui 2011-04-02
  • 打赏
  • 举报
回复
select t.* from tb t where id in (select top 2 id from tb where Type = t.Type order by id)

34,588

社区成员

发帖
与我相关
我的任务
社区描述
MS-SQL Server相关内容讨论专区
社区管理员
  • 基础类社区
  • 二月十六
  • 卖水果的net
加入社区
  • 近7日
  • 近30日
  • 至今
社区公告
暂无公告

试试用AI创作助手写篇文章吧