字节转换问题

[kaonilaomua]

String s="ffffffff";我想用s表示一个4字节的地址，请个位高手，大侠怎么转换

[茫茫大海]

String s = "ffffffff";
byte[] bytes = s.getBytes();

[kaonilaomua]

我的bytes是固定的长度是4，要把s放入

[龙四]

byte[4]占的字节绝对超过4个啊，byte[]是个对象，里面还有一个length属性，是int类型，就超过4字节了

[龙四]

public class Test {
	public static int address2Int(String address) {
		//参数验证....
		return (int)Long.parseLong(address, 16);
	}
	
	public static String int2Address(int value) {
		return String.format("%08x", value);
	}
	
	public static void main(String[] args) {
		int value = address2Int("ffffffef");
		System.out.println(value);
		String address = int2Address(value);
		System.out.println(address);
	}
}

[kaonilaomua]

问题已解决，代码如下，谢谢各位
private final static byte[] hex = "0123456789ABCDEF".getBytes();

private static int parse(char c) {
if (c >= 'a')
return (c - 'a' + 10) & 0x0f;
if (c >= 'A')
return (c - 'A' + 10) & 0x0f;
return (c - '0') & 0x0f;
}

// 从字节数组到十六进制字符串转换
public static String Bytes2HexString(byte[] b) {
byte[] buff = new byte[2 * b.length];
for (int i = 0; i < b.length; i++) {
buff[2 * i] = hex[(b[i] >> 4) & 0x0f];
buff[2 * i + 1] = hex[b[i] & 0x0f];
}
return new String(buff);
}

// 从十六进制字符串到字节数组转换
public static byte[] HexString2Bytes(String hexstr) {
byte[] b = new byte[hexstr.length() / 2];
int j = 0;
for (int i = 0; i < b.length; i++) {
char c0 = hexstr.charAt(j++);
char c1 = hexstr.charAt(j++);
b[i] = (byte) ((parse(c0) << 4) | parse(c1));
}
return b;

[kaonilaomua]

高手快来啊

[茫茫大海]

String s = "ffffffff";
		Long i = Long.parseLong(s, 16);
		System.out.println(Long.toHexString(i));
		System.out.println(Long.toBinaryString(i));
		System.out.println(i);

[kaonilaomua]

我要把它放到byte bytes=new byte[4];中怎么放，请赐教