线程问题

[成一粒]

import java.util.*;
public class test02 implements Runnable{
private int i=0;
private int []a;
private Thread h1;
test02(){
a=new int[6];
h1=new Thread();
}
public void run(){
System.out.println("---------");
this.i++;
Random a=new Random();
this.a[this.i]=a.nextInt(9);
System.out.println("---------");
System.out.println(a);
}

public String toString(){

return a.toString();
}
public static void main(String[] args) throws InterruptedException{
new test02().h1.start();
Thread.sleep(1000*6);
System.out.println("game over!");
}
}
这个程序中怎么输不出数组a的字符串？？

[java爱好者]

package test;

import java.util.Random;

public class test02 implements Runnable {
	private int i = 0;
	private int[] a;
	private Thread h1;

	test02() {
		a = new int[6];
		h1 = new Thread(this);// 需要给线程传入实现Runnable接口的实现类
	}

	public void run() {
		System.out.println("---------");
		this.i++;
		Random a = new Random();
		this.a[this.i] = a.nextInt(9);
		System.out.println("---------");
		System.out.println(this.a[this.i]);// 输出数组中格的某个值。如果全输出run方法需要用循环
	}

	public String toString() {

		return a.toString();
	}

	public static void main(String[] args) throws InterruptedException {
		new test02().h1.start();
		Thread.sleep(1000 * 6);
		System.out.println("game over!");
	}
}

[Ganymede]

implements Runnable改成 extends Thread试试

[Luger]

import java.util.*;

public class Test implements Runnable {
	private int i = 0;
	private int[] a;
	private Thread h1;

	Test() {
		a = new int[6];
		h1 = new Thread(this);    //加上个this试试
	} 

	public void run() {
		System.out.println("---------");
		this.i++;
		Random a = new Random();
		this.a[this.i] = a.nextInt(9);
		System.out.println("---------");
		System.out.println(a);
	}

	public String toString() {

		return a.toString();
	}

	public static void main(String[] args) throws InterruptedException {
		new Test().h1.start();
		Thread.sleep(1000 * 6);
		System.out.println("game over!");
	}
}

[成一粒]

谢谢大侠！i know!