error LNK2019: 无法解析的外部符号 "class std::basic_ostream

//CirQueue.h文件

#include <iostream>

using namespace std;

//循环队列类

template<class Type>

class CirQueue

{

public:

	CirQueue(int size);

	~CirQueue();

	void Store(int n);//初始数据存入

	friend ostream& operator<<(ostream& output,CirQueue<Type>& cq);

private:

	int *data;

	int maxSize;

	int head,rear;

	int length;

};

//构造函数

template<class Type>

CirQueue<Type>::CirQueue(int size)

{

	if(size<1)

		throw "空间大小有误！";

	maxSize=size;

	data=new int[maxSize];

	head=0;

	rear=0;

	length=0;

}

//析构函数

template<class Type>

CirQueue<Type>::~CirQueue()

{

	delete [] data;

	maxSize=0;

	head=rear=-1;

	length=0;

	cout<<"测试析构是否成功"<<endl;

}

//初始数据存入空队列

template<class Type>

void CirQueue<Type>::Store(int n)

{

	if(n<1 || n>maxSize-1)

		throw "输入的数据量大小小于1或超长！";

	for(int i=0; i<n; i++)

	{

		cin>>data[i];

	}

	rear=n;

	length=n;

}

//重载输出队列元素

template<class Type>

ostream& operator<<(ostream& output,CirQueue<Type>& cq)

{

	output<<"测试一下"<<endl;

	/*

	int i=cq.head;

	if(cq.length==0)

		output<<"队列为空！"<<endl;

	if(cq.length==1)

		output<<"惟一元素："<<cq.data[i]<<endl;

	else

	{

		while(i!=cq.rear)

		{

			if(i==cq.head)

				output<<"对头元素："<<cq.data[i]<<endl;

			else if(i==cq.rear-1)

				output<<"对尾元素："<<cq.data[i]<<endl;

			else

				output<<cq.data[i]<<endl;

			i=(i+1)%cq.maxSize;//【妙】

		}

	}

	*/

	return output;

}



//CirQueue_main.cpp

#include <iostream>

using namespace std;

#include "CirQueue.h"



int main()

{

	int size;

	cout<<"请输入队列空间大小：";

	cin>>size;

	CirQueue<int> *cirQ;

	try

	{

		cirQ=new CirQueue<int>(size);

	}

	catch(char *p)

	{

		cout<<p<<endl;

		exit(1);

	}

	int n;

	cout<<"初始数据存入"<<endl;

	cout<<"请输入要存入的数据量大小：";

	cin>>n;

	try

	{

		cout<<"请输入这"<<n<<"个数："<<endl;

		cirQ->Store(n);

	}

	catch(char *p)

	{

		cout<<p<<endl;

		exit(1);

	}

	int choice;

	do

	{

		cout<<endl;

		cout<<"1-进队"<<endl;

		cout<<"2-出队"<<endl;

		cout<<"3-返回对头元素"<<endl;

		cout<<"4-返回队尾元素"<<endl;

		cout<<"5-返回对头、队尾位置"<<endl;

		cout<<"6-返回队列长度"<<endl;

		cout<<"7-输出队列中的元素"<<endl;

		cout<<"8-退出"<<endl;

		cout<<endl;

		cout<<"请输入选项：";

		cin>>choice;

		switch(choice)

		{

		case 7:

			cout<<(*cirQ)<<endl;

			break;

		case 8:

			break;

		default:

			cout<<"无此选项！"<<endl;

			break;

		}

	}while(choice!=8);

	delete cirQ;//①【重点】加上这个语句才执行析构函数



	return 0;

}



/*

下面是连接错误（VS2008、VS2010）



1>CirQueue_main.obj : error LNK2019: 无法解析的外部符号 "class std::basic_ostream<char,struct std::char_traits<char> > & __cdecl operator<<(class std::basic_ostream<char,struct std::char_traits<char> > &,class CirQueue<int> &)" (??6@YAAAV?$basic_ostream@DU?$char_traits@D@std@@@std@@AAV01@AAV?$CirQueue@H@@@Z)，该符号在函数 __catch$_main$0 中被引用

1>F:\编程\CirQueue\Debug\CirQueue.exe : fatal error LNK1120: 1 个无法解析的外部命令

*/