如何将二进制的串转换为字符串

[wuzhi11love]

例如char *p="abcd“；那将*P转换为二进制字符串就是：01100001011000100110001101100100，

#include<stdio.h>
void main()
{
 char *s="abcd";
unsigned char *p=s;
int i=0;
for(;*p!=0;p++)
{
  for ( i=7;i>=0;i--)
  {
  unsigned char a=0;
  unsigned char b=0x01;
  a=( (*p)>>i )&b; /*可见内循环*p的值是不变的 */
  printf("%u",a);
  }
}
}//这是将*s转换为二进制的代码

[ningto.com]

读8位保持起来再继续读下一个8位保持起来读到结尾为止，最后把保持的串联成一个字符串

[ouyh12345]

读8位，然后转换成int

[luciferisnotsatan]

	char buf[9] = {0};
	char *s="abcd";
    char *p = s;
	while('\0' != *p)
	{
		itoa(*p, buf, 2);
		printf("%08s,",buf);
		p++;
	}

	char buf[9] = {0};
	char *s="01100001011000100110001101100100";
    char *p = s;
	char *end = NULL;
	unsigned char c;
	while('\0' != *p)
	{	
		memcpy(buf,p,8);
		c = (char)strtol(buf,&end,2);
		p+=8;
		printf("%c",c);
	}

[luciferisnotsatan]

不用函数，自己写的话

	char *s="01100001011000100110001101100100";
    char *p = s;
	unsigned char c;
	while('\0' != *p)
	{	
		c = 0;
		for(int i = 0; i < 8; i++)
		{
			c = (c << 1) + *p - '0';
			p++;
		}
		printf("%c",c);
	}

[panasonic0804]

二进制的内容不应该是1010101111001101吗？

[screwzm]

[Quote=引用 3 楼 luciferisnotsatan 的回复:]

C/C++ code
char buf[9] = {0};
char *s="abcd";
char *p = s;
while('\0' != *p)
{
itoa(*p, buf, 2);
printf("%08s,",buf);
p++;
}



C/C++ code
char……
[/Quote]
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