请教一下用正则式去字符串的问题

[zhuwen9]

Select * from tabA t where 1=1 and id in (slect * from tabB b wehre #[adsds])and #[t.id||t.name||t.org||t.money]

获取 #[] 之间的字符串

adsds

t.id||t.name||t.org||t.money

[若鱼1919]

public static void main(String[] args) {
		String str = "Select * from tabA t where 1=1 and id in (slect * from tabB b wehre #[adsds])and #[t.id||t.name||t.org||t.money]";
		Matcher m = Pattern.compile("#\\[(.*?)\\]").matcher(str);
		while(m.find()){
			System.out.println(m.group(1));
		}
	}

[steryzone]

[Quote=引用 1 楼 goldenfish1919 的回复:]
Java code

public static void main(String[] args) {
String str = "Select * from tabA t where 1=1 and id in (slect * from tabB b wehre #[adsds])and #[t.id||t.name||t.org||t.money]";
……
[/Quote]

+1