row_number()函数纠结的用法。

[cheniqit1]

table title
id name
1 2
2 3

table line
id title_id name key_index
1 1 A 2
2 1 B 4
3 2 C 1


用row_number()函数根据key_index顺序，注意此字段不连续、
出现如下结果
line_id name row_name
1 A 1
2 B 2
3 C 1

[--小F--]

select
 id,name,row_number() over(partition by title_id order by id) as row_name
from
 tb

[kingtiy]

row_number()over(order by key_index) as row_name

[快溜]

select *,row_name=row_number() over(partition by title_id order by key_index)
from line

[叶子]

declare @line table (id int,title_id int,name varchar(1),key_index int)
insert into @line
select 1,1,'A',2 union all
select 2,1,'B',4 union all
select 3,2,'C',1

select id,name,row_number() over(partition by title_id order by id) as row_name
from @line
/*
id          name row_name
----------- ---- --------------------
1           A    1
2           B    2
3           C    1
*/

[快溜]

declare @Table table (line_ID int,TITLE_ID int,NAME varchar(4),KEY_INDEX int)
insert into @Table
select 1,1,'A',2 union all
select 2,1,'B',4 union all
select 3,2,'C',1 

select line_ID,name,row_name=row_number() over(partition by title_id order by key_index)
from @Table
/*
line_ID     name row_name
----------- ---- --------------------
1           A    1
2           B    2
3           C    1