数组分割字符串

[pingsuccess]

将例如:String temp=",2011,,,";

将它分割成String[] str={"","2011","",""};

谢谢各位了，帮帮忙啦！

[pingsuccess]

[Quote=引用 7 楼 steryzone 的回复:]
Java code

String str = ",2011,,,";
str = str.replaceAll(",",", ");
String[] str1 = str.split("\\,");
[/Quote]

这种的是不可以的，这样的话，显示出来的值中包含空格

[pingsuccess]

[Quote=引用 8 楼 lin186 的回复:]
Java code

String no = "123,456,789,,,,";
no = no.replace(",,", ", ,");//将两个逗号之间加个空格
String[] nos = no.split(",");
for(int i=0;i<nos.length;i++){
System.out.p……
[/Quote]

这样显示出来的值中包含空格，是不行的

[Mr傅]

覆盖String类的split方法吧，呵呵。

[steryzone]

[Quote=引用 11 楼 pingsuccess 的回复:]
引用 7 楼 steryzone 的回复:
Java code

String str = ",2011,,,";
str = str.replaceAll(",",", ");
String[] str1 = str.split("\\,");


这种的是不可以的，这样的话，显示出来的值中包含空格
[/Quote]
那用正式表达式呢

[ETCentury]

public class StringSplit {

	public static void main(String args[]){
		String temp=",2011,,,";
		String[] str = temp.split(",", -1);
		for(String c : str){
			System.out.println("标示开始" + c + "标示结束");
		}
	}
}

这个就可以了

[dangerous_]

  public static void main(String[] args)
    {
        String str = ",,123,,";
        String substr = str;
        int count = 0;
        while (substr.contains(","))
        {
            substr = substr.substring(substr.indexOf(",")+1);
            count ++;
        }
        String[] arr = str.split(",", count + 1);
        for (int i = 0; i < arr.length; i++)
        {
            System.out.println(String.format("%s %s", i, arr[i]));
        }
    }

[dangerous_]

刚刚测试的 没有问题

[休谱诺斯]

[Quote=引用 8 楼 lin186 的回复:]

Java code

String no = "123,456,789,,,,";
no = no.replace(",,", ", ,");//将两个逗号之间加个空格
String[] nos = no.split(",");
for(int i=0;i<nos.length;i++){
System.out.print……
[/Quote]这个比较好

[JavaMan_KA]

public class Test {
public static void main(String[] args) {
String string="a，b，c，d，e ，f，g";
String Count[] = string.split("，"); //遇到空格就拆分。
for(int i=0;i<Count.length;i++)
{
System.out.println(Count[i]); //输出数组Count的数
}
}
}

[wangjiangbo2]

temp.replaceAll(",",",#")
temp.split("#")
没测试不知道可以不

[ForUForM]

将例如:String temp=",2011,,,";
将它分割成String[] str={"","2011","",""};

String temp=",2011,,,";
String[] tempArrs = temp.split(",");//按字符串中的逗号分割开来；
然后tempArrs 就好比是你上面的str={"","2011","",""};了。

[pingsuccess]

[Quote=引用 1 楼 wangjiangbo2 的回复:]
temp.replaceAll(",",",#")
temp.split("#")
没测试不知道可以不
[/Quote]

不行，你这种就把它变成这种了.String[] str=[",2011,,,"];
把它变成了一个值

[pingsuccess]

[Quote=引用 2 楼 lin186 的回复:]
将例如:String temp=",2011,,,";
将它分割成String[] str={"","2011","",""};

String temp=",2011,,,";
String[] tempArrs = temp.split(",");//按字符串中的逗号分割开来；
然后tempArrs 就好比是你上面的str={"","2011","",""};了。
[/Quote]

这种不行啦，我试过了，因为temp字符串后面的是值是空的，如果以这种方式的话，就成了

tempArrs=["","2011"];这种格式了，好像把后面的值就没了

[steryzone]

String str = ",2011,,,";
		Pattern p = Pattern.compile(".*?\\,");
		Matcher m = p.matcher(str);
		while(m.find()){
			System.out.println(m.group());
		}

[lqh3672]

import java.util.ArrayList;
import java.util.List;

public class Test {
	private List templist = new ArrayList();
	private String lastS = "";

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub

		String temp = ",2011,,,";
		Test test = new Test();
		test.getSplitString(temp);
		String[] rs = new String[test.templist.size()];
		for (int i = 0; i < test.templist.size(); i++) {
			rs[i] = test.templist.get(i).toString();
			System.out.println(i + "---" + test.templist.get(i).toString());
		}
	}

	private void getSplitString(String x) {
		String temp = "";
		if (x.contains(",")) {
			temp = x.substring(0, x.indexOf(","));
			lastS = x.substring(x.indexOf(",") + 1);
			templist.add(temp);
			if (lastS.contains(",")) {
				getSplitString(lastS);
			}
		}
	}
}

乱写，所以不精简，结果在String[] rs

[steryzone]

String str = ",2011,,,";
		str = str.replaceAll(",",", ");
		String[] str1 = str.split("\\,");

[ForUForM]

String no = "123,456,789,,,,";
		no = no.replace(",,", ", ,");//将两个逗号之间加个空格
		String[] nos = no.split(",");
		for(int i=0;i<nos.length;i++){
			System.out.println("nos["+i+"]:"+nos[i]);
		}

输出结果：
nos[0]:123
nos[1]:456
nos[2]:789
nos[3]:
nos[4]:
nos[5]:

[lqh3672]

[Quote=引用 8 楼 lin186 的回复:]
Java code

String no = "123,456,789,,,,";
no = no.replace(",,", ", ,");//将两个逗号之间加个空格
String[] nos = no.split(",");
for(int i=0;i<nos.length;i++){
System.out.p……
[/Quote]
支持简洁