std::cout和printf的问题

[myj870517]

#include "stdafx.h"
#include <iostream>
#include <stdio.h>

int _tmain(int argc, _TCHAR* argv[])
{
	typedef struct loc {
		unsigned char a : 4;
		unsigned char b : 4;
	} X;

	X i;
	
	for (i.a = 1; i.a <= 9; ++i.a)
		for (i.b = 1; i.b <= 9; ++i.b)
			if (i.a % 3 != i.b % 3)
				printf("A = %d, B = %d\n", i.a, i.b);
				//std::cout << "x = " << i.a << ",y = " << i.b << std::endl;

	return 0;
}

没注释掉的输出正确,大概这样.
A = 1, B = 2
A = 1, B = 3
A = 1, B = 5
A = 1, B = 6
A = 1, B = 8
A = 1, B = 9
A = 2, B = 1
A = 2, B = 3
A = 2, B = 4
A = 2, B = 6
A = 2, B = 7
A = 2, B = 9
A = 3, B = 1
A = 3, B = 2

注释掉的是我自己随便试的,复制出来没效果(下面),我机器上显示是红桃黑桃什么的乱码,机箱还有"滴滴的声音"很囧,神马原因呢?
x = ,y =
x = ,y =
x = ,y =
x = ,y =
x = ,y =
x = ,y =
x = ,y =
x = ,y =
x = ,y =
x = ,y =
x = ,y =
x = ,y =
x = ,y =

[無_1024]

#include <iostream>
#include <stdio.h>

int main()
{
    typedef struct loc 
	{
        unsigned char a : 4;
        unsigned char b : 4;
    } X;

    X i;
    
    for (i.a = 1; i.a <= 9; ++i.a)
        for (i.b = 1; i.b <= 9; ++i.b)
            if (i.a % 3 != i.b % 3)
                //printf("A = %d, B = %d\n", i.a, i.b);
                std::cout << "x = " << (int)i.a << ",y = " << (int)i.b << std::endl;

    return 0;
}

[無_1024]

没强制转换的时候就是输出char类型的

[xmu_才盛]

[Quote=引用 2 楼 hnuqinhuan 的回复:]
没强制转换的时候就是输出char类型的
[/Quote]

你按照%d打印 声明域后的 字符串， 肯定会出问题。。

[myj870517]

哦原来是这样，我听见滴滴的声音鸡冻了，不好意思。。。