java小题，求解

[Peng_Lu_Blog]

从键盘输入一个整数（1~20）
则以该数字为矩阵的大小，把1,2,3…n*n 的数字按照顺时针螺旋的形式填入其中。例如：
输入数字2，则程序输出：
1 2
4 3
输入数字3，则程序输出：
1 2 3
8 9 4
7 6 5
输入数字4， 则程序输出：
1 2 3 4
12 13 14 5
11 16 15 6
10 9 8 7

[CSDW]

http://blog.sina.com.cn/s/blog_7ea6850b0100qof0.html

[fengyun817]

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Test4 {
	public static void main(String[] args) {
	try {
			int num = 1;
			int cirCle[][] = new int[20][20];
			int i, j, line, t;
			System.out.println("请输入一个正整数");
			InputStreamReader reader = new InputStreamReader(System.in);
			BufferedReader input = new BufferedReader(reader);
			String s = input.readLine();/* 执行输入流操作 */
			int inputNum = Integer.parseInt(s);/* 加个int型的转换 */
			System.out.println(inputNum);
			line = inputNum;

			for (t = 0; t < line; t++) {
				for (i = t, j = t; j < inputNum - t; j++) { // 赋值上外围
					cirCle[i][j] = num;
					num++;
				}
				for (j = j - 1, i = i + 1; i < inputNum - t; i++) { // 赋值右外围
					cirCle[i][j] = num;
					num++;
				}
				for (j = j - 1, i = i - 1; j >= t; j--) { // 赋值下外围
					cirCle[i][j] = num;
					num++;
				}
				for (j = j + 1, i = i - 1; i > t; i--) { // 赋值左外围
					cirCle[i][j] = num;
					num++;
				}

			}
			
			for (int m = 0; m < line; m++) { // 输出结果
				for (int n = 0; n < line; n++) {
					System.out.print(cirCle[m][n] + "\t");
				}
				System.out.println();
			}
		} catch (NumberFormatException e) {
			e.printStackTrace();
		} catch (IOException e) {
			e.printStackTrace();
		}
	}
}

[qiu17717113]

你们真快！楼主 可以结题啦

[叶涛网站推广优化]

public class Test4 {
public static void main(String[] args) {
try {
int num = 1;
int cirCle[][] = new int[20][20];
int i, j, line, t;
System.out.println("请输入一个正整数");
InputStreamReader reader = new InputStreamReader(System.in);
BufferedReader input = new BufferedReader(reader);
String s = input.readLine();/* 执行输入流操作 */
int inputNum = Integer.parseInt(s);/* 加个int型的转换 */
System.out.println(inputNum);
line = inputNum;

for (t = 0; t < line; t++) {
for (i = t, j = t; j < inputNum - t; j++) { // 赋值上外围
cirCle[i][j] = num;
num++;
}
for (j = j - 1, i = i + 1; i < inputNum - t; i++) { // 赋值右外围
cirCle[i][j] = num;
num++;
}
for (j = j - 1, i = i - 1; j >= t; j--) { // 赋值下外围
cirCle[i][j] = num;
num++;
}
for (j = j + 1, i = i - 1; i > t; i--) { // 赋值左外围
cirCle[i][j] = num;
num++;
}

}

for (int m = 0; m < line; m++) { // 输出结果
for (int n = 0; n < line; n++) {
System.out.print(cirCle[m][n] + "\t");
}
System.out.println();
}
} catch (NumberFormatException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}

[jxtg208]

have a look ~~

[陈字文]

[Quote=引用 2 楼 fengyun817 的回复:]

Java code


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Test4 {
public static void main(String[] args) {
try {
int ……
[/Quote]


so.....

[tianmaxingkong139]

强人啊。膜拜