拆分一张表中的一个字段，并且将拆分开的内容生产一张新表

[eternity88]

方法我在网上已经搜索出来了，但是不知道咋调用到表中

方法如下:
CREATE OR REPLACE TYPE ty_str_split IS TABLE OF VARCHAR2 (4000);
CREATE OR REPLACE FUNCTION fn_split (p_str IN VARCHAR2, p_delimiter IN VARCHAR2)
RETURN ty_str_split
IS
j INT := 0;
i INT := 1;
len INT := 0;
len1 INT := 0;
str VARCHAR2 (4000);
str_split ty_str_split := ty_str_split ();
BEGIN
len := LENGTH (p_str);
len1 := LENGTH (p_delimiter);
WHILE j < len
LOOP
j := INSTR (p_str, p_delimiter, i);
IF j = 0
THEN
j := len;
str := SUBSTR (p_str, i);
str_split.EXTEND;
str_split (str_split.COUNT) := str;
IF i >= len
THEN
EXIT;
END IF;
ELSE
str := SUBSTR (p_str, i, j - i);
i := j + len1;
str_split.EXTEND;
str_split (str_split.COUNT) := str;
END IF;
END LOOP;
RETURN str_split;
END fn_split;



调用：
单独拆分一个字符
如：select fn_split('a,b,c,aa,d',',') from dual
执行结果是
a
b
c
aa
d

但如果我是要拆分表A中的 d字段内容呢 A表有很多条记录。我该怎么用，求帮忙

[tangren]

采用游标针对每一行调用fn_split

[304的的哥]

SQL> create table ta as
  2  select 'a,b,c,aa,d' chr from dual
  3  /
 
Table created
 
SQL> select * from ta;
 
CHR
----------
a,b,c,aa,d

SQL> create table tb as
  2  select * from ta
  3  where 1=0
  4  /
 
Table created
 
SQL> select count(*) from tb;
 
  COUNT(*)
----------
         0
SQL> insert into tb
  2  select regexp_substr(chr,'[^,]+',1,level) chr
  3  from ta
  4  connect by
  5          level <= length(chr)-
  6          length(replace(chr,',',''))+1
  7  /
 
5 rows inserted
 
SQL> select * from tb;
 
CHR
----------
a
b
c
aa
d
 
SQL> 

[eternity88]

我的'a,b,c,aa,d' 只是舉例 如果我要把這個內容 換成是表中的某個字段要怎麼辦

[gelyon]

with tab as(
select 'test' name,'a,b,c,aa,d' id from dual
)
select name,regexp_substr(id,'[^,]+',1,level) as newid
from tab
connect by
level<=length(id)-length(replace(id,',',''))+1

NAME NEWID
------------
test  a 
test  b 
test  c 
test  aa
test  d 

[eternity88]

能否提供點注解.
如果用遊標是怎麼寫

[eternity88]

[Quote=引用 1 楼 tangren 的回复:]
采用游标针对每一行调用fn_split
[/Quote]

能给个详解吗？