求一个二叉树的完整程序,包括前序遍历创建二叉树，线索化，中序遍历二叉树，C语言版的！

[shaoxiaojing5193]

求一个二叉树的完整程序,包括三个函数：前序遍历创建二叉树，线索化二叉树，中序遍历二叉树。C语言版的！小弟是初学者阿，希望前辈帮忙写个完整的程序，小弟在此先感谢了！（是普通的二叉树噢，小弟刚学。）

[w74839520]

数据结构 C语言版本 上面有。清华大学的。

好像是伪代码。

[shaoxiaojing5193]

嗯，我知道阿，我现在想要完整的代码，光理解了算法还是不够的。。。

[yfk]

#include<stdlib.h>
#include<stdio.h>
#define MAX  50
#define MAS  20
#define CHAR 1
#if CHAR
   typedef char TElemType;
   TElemType Nil=' ';
   #define form "%c"
#else
   typedef int TElemType;
   TElemType Nil=0;
   #define form "%d"
#endif
typedef struct node
{TElemType data;
 struct node *left;
 struct node *right;
 struct node *parent;
}BiTNode,*BiTree;
BiTNode *InitBiTree(BiTNode *bt)
{
 bt=NULL;
 return bt;
}
BiTNode *CreateBiTree(BiTNode *bt)
{TElemType ch;
 scanf(form,&ch);
 if(ch==Nil) bt=NULL;
  else
  {bt=(BiTNode *)malloc(sizeof(BiTNode));
   if(!bt) exit(0);
   bt->data=ch; bt->parent=NULL;
   bt->left=CreateBiTree(bt->left);
   if(bt->left) bt->left->parent=bt;
   bt->right=CreateBiTree(bt->right);
   if(bt->right) bt->right->parent=bt;
  }
  return bt;
}
void PrintTree(BiTNode *bt,int i)
{ if(bt!=NULL)
  {PrintTree(bt->right,i+5);
   #if CHAR
    if(bt->data!=Nil)
    printf("%*c\n",i,bt->data);
   #else
    if(bt->data!=Nil)
    printf("%*d\n",i,bt->data);
   #endif
   PrintTree(bt->left,i+5);
   i=i-5;
  }
}
void Prorder1(BiTNode *bt,void(*visit)(TElemType))/*先序遍历*/
{if(bt!=NULL)
 {visit(bt->data);
  Prorder1(bt->left,visit);
  Prorder1(bt->right,visit);
 }
}
void Prorder2(BiTNode *bt,void(*visit)(TElemType))/*中序遍历*/
{BiTNode *p,*stack[MAS];
 int top;
 top=0;  p=bt;
 while(top!=0||p!=NULL)
 {while(p!=NULL)
  {stack[top]=p; top++;
   p=p->left;
  }
  if(top!=0)
  {p=stack[top-1];
   top--;
   visit(p->data);
   p=p->right;
  }
 }
}
void Prorder3(BiTNode *bt,void(*visit)(TElemType))/*后序遍历*/
{BiTNode *p,*stack[MAS];
 int top;
 top=0;
 stack[top]=bt; top++;
 while(top>0)
 {p=stack[top-1]; top--;
  while(p!=NULL)
  {visit(p->data);
   stack[top]=p->right;
   top++;
   p=p->left;
  }
 }
}
void visit(TElemType e)
{printf(form" ",e);
}
int SumLefts(BiTNode *bt,int sum)
{
 if (bt!=NULL)
  {
    if (bt->left==NULL && bt->right==NULL)
    {
      printf("%4c",bt->data); sum++;
    }
   sum=SumLefts(bt->left,sum);
   sum=SumLefts(bt->right,sum);
  }
 return(sum);
}
int SumTree(BiTNode *bt)
{static int sum=0;
 if(bt!=NULL)
 {printf("%4c",bt->data);
  sum++;
  sum=SumTree(bt->left);
  sum=SumTree(bt->right);
 }
 return(sum);
}
BiTNode *Findchar(BiTNode *bt,char ch)      /*二叉树查找结点*/
{BiTNode *p;     /*利用函数名返回结果*/
 if(bt!=NULL)
 {if(bt->data==ch) p=bt;
  p=Findchar(bt->left,ch);
  p=Findchar(bt->right,ch);
 }
 if(p!=NULL) return(p);
 else return(NULL);
}

main()
{ int j,i,a,sum=0;
  BiTree bt;
  bt=InitBiTree(bt);
  #if CHAR
   printf("请先序输入二叉树(如:ab三个空格表示a为根结点,b为左子树的二叉树)\n");
  #else
   printf("请先序输入二叉树(如:1 2 0 0 0表示1为根结点,2为左子树的二叉树)\n");
  #endif
  bt=CreateBiTree(bt);
  printf("输入建立的二叉树!!!\n");
  PrintTree(bt,5);
  do{
     printf("------------------------------------------------------------");
     printf("\n     主菜单");
     printf("\n  1  二叉树先序遍历");
      printf("\n  2  二叉树中序遍历");
     printf("\n  3  二叉树后序遍历");
     printf("\n  4  二叉树叶子结点数");
     printf("\n  5  二叉树结点数");
     printf("\n  6  二叉树查找x结点");
     printf("\n  0     退出");
     printf("\n----------------------------------------------------------");
     printf("\n");
     printf("输入你要选择的数据:");
     scanf("%d",&i);
     switch(i)
       {case 1: printf("先序遍历结果为:");
         Prorder1(bt,visit);
         break;
        case 2: printf("后序遍历结果为:");
         Prorder2(bt,visit);
         break;
        case 3: printf("中序遍历结果为:");
         Prorder3(bt,visit);
         break;
        case 4: j=SumLefts(bt,sum);
         printf("树的叶子结点数为%d:",j);
         break;
        case 5: j=SumTree(bt);
         printf("树的结点数为%d:",j);
         break;
        case 6: printf("输入要查找的结点字符x:");
         scanf("%c",&a); scanf("%*c");
         j=Findchar(bt,a);
         printf("要查找的结点的指针为%d:",j);
         break;
        case 0: exit(0);
       }
 printf("\n");
 getch();
    }while(i>0||i<8);
}

[shaoxiaojing5193]

我要有线索化的阿，还有标志域 lrag，rrag的结构。。。

[newfarmerchi]

#include<iostream.h>
#include<stdlib.h>
#include<string.h>
#include<stdio.h>

struct node
{
char data;
node *rchild,*lchild;
int rtag,ltag;
};

void create(node *&b)//创建二叉树
{
char c;
c=getchar();
getchar();//吸收回车，清空
if(c==' ')
b=NULL;
else
{
b=(node *)malloc(sizeof(node));
b->data=c;
b->rtag=0;
b->ltag=0;
create(b->lchild);
create(b->rchild);
}
}

void zxbl(node *b)//中序遍历
{
if(b!=NULL)
{
zxbl(b->lchild);
cout<<b->data;
zxbl(b->rchild);
}
}

node *pre=NULL;

void thread(node *&b)
{
if(b!=NULL)
{
thread(b->lchild);
if(b->lchild==NULL)
{
b->lchild=pre;
b->ltag=1;
}
//else
//b->ltag=0;
if(pre->rchild==NULL)
{
pre->rchild=b;
pre->rtag=1;
}
//else
//pre->rtag=0;
pre=b;
thread(b->rchild);
}
}
node * xstree(node *b)
{
node *root=(node *)malloc(sizeof(node));
root->rtag=1;
root->ltag=0;
root->rchild=root;
if(b==NULL)
root->lchild=root;
else
{
root->lchild=b;
pre=root;
thread(b);
pre->rchild=root;
pre->rtag=1;
root->rchild=pre;
}
return root;
}

void shuchu(node *b)
{
node *p=b->lchild;
while(p!=b)
{
while(p->ltag==0)
p=p->lchild;
cout<<p->data;
while(p->rtag==1&&p->rchild!=b)
{
p=p->rchild;
cout<<p->data;
}
p=p->rchild;
}
cout<<endl;
}





void main()
{
node *root;
cout<<"请输入二叉树的先序遍历序列，以建立二叉树："<<endl;
create(root);
cout<<"二叉树的中序遍历为:";
zxbl(root);
cout<<endl;
root=xstree(root);
cout<<"线索二叉树的输出:";
shuchu(root);
}