字符串数组问题

妖妖灵_1 2011-06-08 06:02:10

unsigned char char_num = {"1234567890"}
如何转化成0x12 0x34 0x56 0x78 0x90这样的形式？

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小小攻城师 2011-06-08

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看错题目了，害我把十进制转化成十六进制....

#include <stdio.h>

#include <string.h>

int main()

{

	char char_num[] = {"1234567890"};

	int hex_num[5];

	char buf[5];

	int i;

	for(i = 0; i < 5; i++){

		strncpy(buf, char_num+2*i, 2);

		strcat(buf, "0x");

		sscanf(buf, "%d", &hex_num[i]);

		printf("0x%d ", hex_num[i]);

	}

	return 0;

}

运行结果：

0x12 0x34 0x56 0x78 0x90

小小攻城师 2011-06-08

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#include <stdio.h>

#include <string.h>

int main()

{

	char char_num[] = {"1234567890"};

	int hex_num[5];

	char buf[5];

	int i;

	for(i = 0; i < 5; i++){

		strncpy(buf, char_num+2*i, 2);

		strcat(buf, "0x");

		sscanf(buf, "%x", &hex_num[i]);

		printf("0x%d ", hex_num[i]);

	}

	return 0;

}

运行结果：

0x18 0x52 0x86 0x120 0x144

ryfdizuo 2011-06-08

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#include <stdio.h>

#include <stdlib.h>

#include <string.h>





int main(int argc,char* argv[])

{

	unsigned char char_num[] = {"1234567890"};

	

	unsigned char *p = char_num;

	

	unsigned char result[10];



	int idx = 0;

	while (*p)

	{	

		int temp1 = *p++ - '0';

		int temp2 = *p - '0';



		result[idx] = temp1*16 + temp2;

		

		++idx;

		++p;

	}



	for (int i=0; i<idx; i++)

		printf("%d\n", result[i]);



	system("PAUSE");



	return 0;

}

18

52

86

120

144

请按任意键继续. . .

妖妖灵_1 2011-06-08

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unsigned char char_num[] = {"1234567890"}
unsigned char hex_num[] = {0x12,0x34,0x56,0x78,0x90}

ryfdizuo 2011-06-08

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#include <stdio.h>

#include <stdlib.h>

#include <string.h>





int main(int argc,char* argv[])

{

	unsigned char char_num[] = {"1234567890"};

	

	unsigned char *p = char_num;

	

	char string[50][5];



	int idx = 0;

	while (*p)

	{	

		sprintf(string[idx], "0x%c%c", p[0], p[1]);		



		puts(string[idx]);

		++idx;

		++p;

		++p;

	}



	system("PAUSE");



	return 0;

}