怎么把double转换成字符串?

[mostone]

小数位是固定还是可变的?

[ryfdizuo]

stringstream

[hedy007]

#include <stdlib.h>
#include <stdio.h>

void main( void )
{
   int  decimal, sign;
   char *buffer;
   double source = 3.1415926535;

   buffer = _fcvt( source, 7, &decimal, &sign );
   printf( "source: %2.10f   buffer: '%s'   decimal: %d   sign: %d\n",
            source, buffer, decimal, sign );
}

[ryfdizuo]

#include <stdio.h>

int main ()
{
	char buffer [50];
	double d = 0.12345;
	int n = sprintf (buffer, "%lf", d);
	printf ("[%s] is a %d char long string\n",buffer, n);
	return 0;
}
[0.123450] is a 8 char long string

[ryfdizuo]

#include <iostream>
#include <sstream>
#include <limits>

using namespace std;

int main()
{
    int prec = numeric_limits<double>::digits10;
    double a = 123.123456789123;
    stringstream ss;
    ss.precision(prec);
    ss << a;
    cout << ss.str() << " = " << ss.str().length();

    return 0;
}

[liutengfeigo]

哦,都可以.

[5t4rk]

//楼主我举个例子吧

char tmp[255];
double dex;
dex=16645.00;
memset( tmp,0x00,sizeof( tmp ) );//初始化数组
sprintf( tmp,"%f",dex ); //此处就是实现的转换函数
printf("%s",tmp);

希望有用

[我的职业是看店铺的]

收藏，关注下！

[W1nds]

sprintf

[gaoyuqiang20]

sprintf函数挺给力的

[pathuang68]

[Quote=引用 3 楼 dizuo 的回复:]

C/C++ code
#include <stdio.h>

int main ()
{
char buffer [50];
double d = 0.12345;
int n = sprintf (buffer, "%lf", d);
printf ("[%s] is a %d char long string\n",buffer, n);
retur……
[/Quote]

++
支持这种办法。

[aprial2013]

本人爱用这种方法。简单通用。 std::ostringstream
[Quote=引用 4 楼 dizuo 的回复:]
C/C++ code

#include <iostream>
#include <sstream>
#include <limits>

using namespace std;

int main()
{
int prec = numeric_limits<double>::digits10;
double a = 123.123456789123;
……
[/Quote]

[QQ515311445]

char Buffer[MAX_PATH] = {0};
double PI = 3.1415926;
sprintf(Buffer,"%lf",PI);

[gz_qmc]

力挺sprintf