C++输出问题

[wadd1990]

编程时输出0x00……是什么问题，这是不是内存地址？

[ryfdizuo]

0x是十六进制

[daivder]

代码呢？

[bdmh]

十六进制表示方法0x

[高性能架构探索]

有可能是内存地址，也有可能是其值以16进制输出

[wadd1990]

[Quote=引用 2 楼 daivder 的回复:]

代码呢？
[/Quote]
想编个des这是我的代码
#include<iostream.h>
#include<stdlib.h>
int text[32];
int tsbox[32];
int rptt[48];
int lpt[32],rpt[32];
int pt[64];
int ptext[64];
int key_pc_1[56];
int lk[28],rk[28];
int tt[64];
int txt[64];
int key2[48];
void inkey(int key[64]) //初始置换
{
int i;
int pc_1[64]={
57, 49, 41, 33, 25, 17, 9, 1, 58, 50, 42, 34, 26, 18,
10, 2, 59, 51, 43, 35, 27, 19, 11, 3, 60, 52, 44, 36,
63, 55, 47, 39, 31, 23, 15, 7, 62, 54, 46, 38, 30, 22,
14, 6, 61, 53, 45, 37, 29, 21, 13, 5, 28, 20, 12, 4};

for(i=0;i<56;i++)
{
key_pc_1[i]=key[pc_1[i]];
}
}


void part(int key_pc_1[56])
{
//分两部分
int i,j=0;
for(i=0;i<28;i++)
{
lk[i]=key_pc_1[i];
}
for(i=28;i<56;i++)
{
rk[j]=key_pc_1[i];
j++;
}
}
void shift(int lk[28],int rk[28]) //移位
{
int temp;
int i;
temp=lk[0];
for(i=0;i<27;i++)
{
lk[i]=lk[i+1];
}
lk[28]=temp;
}
void key_pc_2(int lk[28],int rk[28])
{ //pc_2生成k1
// int*p;
int i,j=0,k=0;
int akey[56];
//int bkey[48];
for(i=0;i<28;i++)
{
akey[j]=lk[i];
akey[j+28]=rk[i];
j++;
}
int pc_2[48]={14, 17, 11, 24, 1, 5, 3, 28, 15, 6, 21, 10,
23, 19, 12, 4, 26, 8, 16, 7, 27, 20, 13, 2,
41, 52, 31, 37, 47, 55, 30, 40, 51, 45, 33, 48,
44, 49, 39, 56, 34, 53, 46, 42, 50, 36, 29, 32};
for(i=0;i<56;i++)
{
key2[k]=akey[pc_2[i]];
}
//p=bkey;
//return *p;

}

void plaintext(int ptext[64]) //明文初始化
{
int i=0;
//int pt[64];
int pint[64]={58, 50, 42, 34, 26, 18, 10, 2, 60, 52, 44, 36, 28, 20, 12, 4,
62, 54, 46, 38, 30, 22, 14, 6, 64, 56, 48, 40, 32, 24, 16, 8,
57, 49, 41, 33, 25, 17, 9, 1, 59, 51, 43, 35, 27, 19, 11, 3,
61, 53, 45, 37, 29, 21, 13, 5, 63, 55, 47, 39, 31, 23, 15, 7};

for(i=0;i<64;i++)
{
pt[i]=ptext[pint[i]];
}
}

void partp(int pt[64]) //明文分成两部分
{
// int etable[48]={32, 1, 2, 3, 4, 5, 4, 5, 6, 7, 8, 9,
// 8, 9, 10, 11, 12, 13, 12, 13, 14, 15, 16, 17,
// 16, 17, 18, 19, 20, 21, 20, 21, 22, 23, 24, 25,
// 24, 25, 26, 27, 28, 29, 28, 29, 30, 31, 32, 1}
int i,j=0;
// int lpt[32];
// int rpt[32];
// int rptt[48];
for(i=0;i<32;i++)
{
lpt[i]=pt[i];
}
for(i=32;i<64;i++)
{
rpt[j]=pt[i];
j++;
}


}

void ebox(int lpt[32],int rpt[32])
{
int i; //e-box
int etable[48]={32, 1, 2, 3, 4, 5, 4, 5, 6, 7, 8, 9,
8, 9, 10, 11, 12, 13, 12, 13, 14, 15, 16, 17,
16, 17, 18, 19, 20, 21, 20, 21, 22, 23, 24, 25,
24, 25, 26, 27, 28, 29, 28, 29, 30, 31, 32, 1};

// int rptt[48];
for(i=0;i<48;i++)
{
rptt[i]=rpt[etable[i]];
}
}

void sbox(int rptt[48],int key2[48])
{
int hang,lie; //s-box
int stable[8][64]={
// S1
14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7,
0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8,
4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0,
15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13,
// S2
15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10,
3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5,
0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15,
13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9,
// S3
10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8,
13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1,
13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7,
1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12,
// S4
7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15,
13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9,
10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4,
3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14,
// S5
2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9,
14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6,
4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14,
11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3,
// S6
12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11,
10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8,
9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6,
4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13,
// S7
4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1,
13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6,
1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2,
6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12,
// S8
13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7,
1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2,
7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8,
2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11
};
//key2=the key after pc_2
int i;
for(i=0;i<48;i++) //xor
{
if(rptt[i]==key2[i])
rptt[i]=0;
else
rptt[i]=1;
}
for(i=0;i<8;i++)
{
hang=rptt[i*6]*2+rptt[i*6+5];
lie=rptt[i*6+1]*8+rptt[i*6+2]*4+rptt[i*6+3]*2+rptt[i*6+4];
tsbox[i*4+3]=stable[i][(hang+1)*16+lie]%2;
tsbox[i*4+2]=(stable[i][(hang+1)*16+lie]/2)%2;
tsbox[i*4+1]=(stable[i][(hang+1)*16+lie]/4)%2;
tsbox[i*4]=(stable[i][(hang+1)*16+lie]/8)%2;
}

}

void pbox(int tsbox[32]) //p-box
{
int i;
int ptable[32]= {
16, 7, 20, 21, 29, 12, 28, 17,
1, 15, 23, 26, 5, 18, 31, 10,
2, 8, 24, 14, 32, 27, 3, 9,
19, 13, 30, 6, 22, 11, 4, 25
};
// int text[32];
for(i=0;i<32;i++)
{
text[i]=tsbox[ptable[i]];
}
}

void xor(int text[32]) //抑或
{
int i;
for(i=0;i<32;i++)
{
if(lpt[i]==text[i])
lpt[i]=0;
else
lpt[i]=1;
}

}
void ftr(int tt[64])
{
int i;
int ft[64]={40, 8, 48, 16, 56, 24, 64, 32, 39, 7, 47, 15, 55, 23, 63, 31,
38, 6, 46, 14, 54, 22, 62, 30, 37, 5, 45, 13, 53, 21, 61, 29,
36, 4, 44, 12, 52, 20, 60, 28, 35, 3, 43, 11, 51, 19, 59, 27,
34, 2, 42, 10, 50, 18, 58, 26, 33, 1, 41, 9, 49, 17, 57, 25};
for(i=0;i<64;i++)
txt[i]=tt[ft[i]];
}


void main()
{
int t;
// int key2[48];
int j=0;
char ckey[8];
int i;
int key[64];
int kkey[56];
cout<<"请输入密钥："<<endl;
for(i=0;i<8;i++)
cin>>ckey[i];


for(i=0;i<8;i++)
{
for(j=7;j>=0;j--)
{
t=ckey[i]/2;
kkey[8*i+j]=ckey[i]%2;
ckey[i]=t;
}
}



// kkey=atoi(ckey);
// for(i=0;i<56;i++)
// {
// kkey[j]=(int)ckey[i];
// j=j+7;
// }
for(i=0;i<64;i++)
{
if(i%8==0)
key[i]=0;
else
{
key[i]=kkey[j];
j++;
}
}
cout<<"密钥是： "<<endl;
cout<<key<<endl;

inkey(key);
part(key_pc_1);
/* for(i=0;i<16;i++)
{
if(i==0||i==1||i==8||i==15)
shift(lk,rk);
shift(lk,rk);
key2=key_pc_2(lk,rk);
}*/
cout<<"请输入明文： "<<endl;
for(i=0;i<64;i++)
cin>>ptext[i];
cout<<"明文是： "<<endl;
cout<<ptext<<endl;
plaintext(ptext);
partp(pt);
for(j=0;j<16;j++)
{
if(i==0||i==1||i==8||i==15)
shift(lk,rk);
shift(lk,rk);
// key2[48]=key_pc_2(lk,rk);


ebox(lpt,rpt);
sbox(rptt,key2);
pbox(tsbox);
xor(text);
int tmp[32];
for(i=0;i<32;i++)
{
tmp[i]=lpt[i];
lpt[i]=rpt[i];
rpt[i]=tmp[i];
}
}
j=0;
for(i=0;i<32;i++)
tt[i]=lpt[i];
for(i=32;i<64;i++)
{
tt[i]=rpt[j];
j++;
}
cout<<"密文是： "<<endl;
cout<<txt<<endl;
}

[ryfdizuo]

key, ptext都是int数组，直接输出当然就是地址咯。
字符数组可以直接输出，

[wadd1990]

改完以后为什么密文输出全是0