关于JQuery 和 WS ScriptMethod(UseHttpGet = true)?

sskset 2011-06-22 12:48:21

请问下,我在WebService方法里定义了[ScriptMethod(UseHttpGet = true)],
然后在JQuery里调用的时候为什么还是要POST才能够取到值?

MSDN 也说是要用GET取值
http://msdn.microsoft.com/zh-cn/library/system.web.script.services.scriptmethodattribute.usehttpget.aspx

在线等到答案就结贴...谢谢啊

Web Service 代码





[ScriptService]

[WebService(Namespace = "http://www.midaske.com/")]

[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]

public class SyncService : System.Web.Services.WebService

{

    public SyncService()

    {



    }



    [WebMethod]

    [ScriptMethod(UseHttpGet = true)]

    public string Hello()

    {

        return "Hello Test";

    }

}

JS代码



<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

    <title></title>

    <script src="Scripts/jquery-1.4.1.min.js" type="text/javascript"></script>

</head>

<body>

    <script type="text/javascript" language="javascript">

        $.ajax({

            url: "Services/SyncService.asmx/Hello",

            type: "post",

            dataType: ($.browser.msie) ? "text" : "xml",

            success: function (data) {

                alert("success");

                var xml;

                if (typeof data == "string") {

                    alert("1");

                    xml = new ActiveXObject("Microsoft.XMLDOM");

                    xml.async = false;

                    xml.loadXML(data);

                } else {

                    alert("2");

                    xml = data;

                }



                var ser = new XMLSerializer();

                alert(ser.serializeToString(xml));

            },

            error: function (e) {

                alert("error");

                alert(e.toString());

            }

        });



    </script>

</body>

</html>

...全文

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子夜__ 2011-06-22

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参考

<script type="text/javascript">



        $(function () {



            /*

            1、WebService请求类型都为Post，WebService的Url为“[WebServiceUrl]/[WebMethod]”

            2、contentType声明为Json

            3、data要用Json的字符串格式传入

            4、设置了dataType为json后，result就直接为返回的Json对象。



            */



            //调用无参数方法

            $("#btnHelloWorld").click(function () {

                $.ajax({

                    type: "POST",

                    contentType: "application/json",

                    url: "WebService1.asmx/HelloWorld",

                    data: "{}",

                    dataType: 'json',

                    success: function (result) {

                        alert(result.d);

                    }

                });

            });



            //传入1个参数

            $("#btnHello").click(function () {

                $.ajax({

                    type: "POST",

                    contentType: "application/json",

                    url: "WebService1.asmx/Hello",

                    data: "{name:'KiMoGiGi'}",

                    dataType: 'json',

                    success: function (result) {

                        alert(result.d);

                    }

                });

            });



            //返回泛型列表

            $("#btnArray").click(function () {

                $.ajax({

                    type: "POST",

                    contentType: "application/json",

                    url: "WebService1.asmx/CreateArray",

                    data: "{i:10}",

                    dataType: 'json',

                    success: function (result) {

                        alert(result.d.join(" | "));

                    }

                });

            });



            //返回复杂类型

            $("#btnPerson").click(function () {

                $.ajax({

                    type: "POST",

                    contentType: "application/json",

                    url: "WebService1.asmx/GetPerson",

                    data: "{name:'KiMoGiGi',age:26}",

                    dataType: 'json',

                    success: function (result) {

                        var person = result.d;

                        var showText = [];

                        for (var p in person) {

                            showText.push(p + ":" + person[p]);

                        }

                        alert(showText.join("\r\n"));

                    }

                });

            });

        });

    

    </script>

HDNGO 2011-06-22

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data:"",
这个加上试试滴~~

HDNGO 2011-06-22

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无参数？GET？
不用那么复杂吧。。。



$.ajax({

                url: "WebService1.asmx/WS3",

                dataType: "json",

                data: "",

                beforeSend: function(x) {

                    x.setRequestHeader("Content-Type", "application/json; charset=utf-8");

                },

                success: function(json) {

                    alert(json.d);

                },

                error: function(x, e) {

                    alert(x.responseText);

                },

                complete: function(x) {

                    alert(x.responseText);

                }

            });