关于日期加1

[demonapple]

我用一个input text填写日期 如2011-06-01
然后提交给另一个页面
用
String time1=request.getParameter("time1");
然后我应该怎么处理
可以让这个time1加1？
变成2011-06-02

[zn85600301]

public static java.util.Date addDate(java.util.Date date, int day) {
java.util.Calendar c = java.util.Calendar.getInstance();
c.setTimeInMillis(getMillis(date) + ((long) day) * 24 * 3600 * 1000);
return c.getTime();
}

[皮皮]

String time1=request.getParameter("time1");
Calendar cstart = Calendar.getInstance();
cstart.setTime(new Date(time1));
cstart.set(Calendar.DAY_OF_YEAR, cstart
.get(Calendar.DAY_OF_YEAR)+1 );

Date newdate= cstart.getTime();

[学无止境+]

你对了

[tubage408]

String[] yMD = "2011-06-01".split("-");
Calendar cal = Calendar.getInstance();
cal.set(Integer.parseInt(yMD[0]), Integer.parseInt(yMD[1]), Integer.parseInt(yMD[2]));
cal.add(Calendar.DATE,1);
System.out.println(cal.get(Calendar.YEAR)+"-"+cal.get(Calendar.MONTH)+"-"+cal.get(Calendar.DATE));

注意12月30号

[风丶子]

[Quote=引用 2 楼 pipi517 的回复:]
String time1=request.getParameter("time1");
Calendar cstart = Calendar.getInstance();
cstart.setTime(new Date(time1));
cstart.set(Calendar.DAY_OF_YEAR, cstart
.get(Calendar.DAY_OF_YEAR)+1 );

Da……
[/Quote]
+1

[demonapple]

String time1=request.getParameter("time1");
Calendar cstart = Calendar.getInstance();
cstart.setTime(new java.util.Date(time1));
cstart.set(Calendar.DAY_OF_YEAR, cstart
.get(Calendar.DAY_OF_YEAR)+1 );

java.util.Date newdate= cstart.getTime();
System.out.println(newdate);

有错误啊。

org.apache.jasper.JasperException: An exception occurred processing JSP page /bb_gzkhzb_do.jsp at line 66

63: </table>
64: <%
65: Calendar cstart = Calendar.getInstance();
66: cstart.setTime(new java.util.Date(time1));
67: cstart.set(Calendar.DAY_OF_YEAR, cstart
68: .get(Calendar.DAY_OF_YEAR)+1 );
69:

java.lang.IllegalArgumentException
java.util.Date.parse(Date.java:598)
java.util.Date.<init>(Date.java:255)
org.apache.jsp.bb_005fgzkhzb_005fdo_jsp._jspService(bb_005fgzkhzb_005fdo_jsp.java:143)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:377)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)

[皮皮]

String time1=request.getParameter("time1");

转为Date

[Fly_m]

使用apache common包
DateUtils.addDays(date1,1)就OK

[hi_kevin]

/**
* 得到几天前的时间
* @param d
* @param day
* @return
*/
public static Date getDateBefore(Date d,int day) throws Exception{
Calendar now =Calendar.getInstance();
now.setTime(d);
now.set(Calendar.DATE,now.get(Calendar.DATE)-day);
return now.getTime();
}

/**
* 得到几天后的时间
* @param d
* @param day
* @return
*/
public static Date getDateAfter(Date d,int day) throws Exception{
Calendar now =Calendar.getInstance();
now.setTime(d);
now.set(Calendar.DATE,now.get(Calendar.DATE)+day);
return now.getTime();
}

[feichexia]

Calendar cal=Calendar.getInstance();
cal.setTime(date); /date是Date类型，是你通过request.getParameter获取的
cal.add(Calendar.DATE, 1);
然后cal.getTime();即得加1后的Date对象。

附上自己写的一个简单日期工具类：

package util;

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;

public class DateUtils {

	/**
	 * 日期转换成字符串
	 * 
	 * @param date
	 * @return str
	 */
	public static String dateToStr(Date date) {

		SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");
		String str = format.format(date);
		return str;
	}

	/**
	 * 字符串转换成日期
	 * 
	 * @param str
	 * @return date
	 */
	public static Date strToDate(String str) {

		SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");
		Date date = null;
		try {
			date = format.parse(str);
		} catch (ParseException e) {
			e.printStackTrace();
		}
		return date;
	}
	
	//获取今天日期
	public static Date getCurrentDate() {
		return new Date();
	}
	
	//获取前n天日期
	public static Date getPrendayDate(int n) {
		Calendar cal=Calendar.getInstance();
		cal.add(Calendar.DATE, -n);
		return cal.getTime();
	}
	
	public static void main(String[]args) {
		System.out.println(getPrendayDate(6));
	}

}

[奔跑吧__小犀牛]

写一个方法，调用一下就行了！
public final static String getTomorrow(String days,String ft, int x) {
SimpleDateFormat sdf = new SimpleDateFormat(ft);
Date today = new Date();
try {
today = sdf.parse(days);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
long d = today.getTime() + (1000 * 60 * 60 * 24) * x;
Date tomDay = new Date(d);
String tomDayStr = sdf.format(tomDay);
return tomDayStr;
}

[凌风雪雕]

做过一次类似的 就是一天过期的

[凌风雪雕]

以前华为在面试过一个类似的问题 一个关于id生成的问题 就是一个月过期吧 然后又可以回收再进行利用的

[HYbdbc]

SimpleDateFormat format_2 = new SimpleDateFormat("yyyy-MM-dd");
                String time1=(String)request.getParameter("time1");
		Date date = null;
		try {
			date = DateFormat.getDateInstance().parse(time1);
		} catch (ParseException e) {
 			e.printStackTrace();
		}
		Calendar cl = Calendar.getInstance();
		cl.setTime(date);
		cl.add(Calendar.DATE, 1);
		System.out.println("日期+1 ： " + format_2.format(cl.getTime()));

[luyulanshan]

谢谢。楼上，我也很需要。

[Phyane]

[Quote=引用 4 楼 tubage408 的回复:]
String[] yMD = "2011-06-01".split("-");
Calendar cal = Calendar.getInstance();
cal.set(Integer.parseInt(yMD[0]), Integer.parseInt(yMD[1]), Integer.parseInt(yMD[2]));
cal.add(Calendar.DATE,1);
Syst……
[/Quote]
你太有才了，这个都能想到，服你了