字符串的截取问题，急急急！！各位大侠帮帮忙呀

[luchangxing09]

例如：我输入任意字符串s[]="begin hkhkhk 7997 ljlj 4567r end"
设计一个程序begin作为程序的开始，end作为程序的结束
最后我要的结果是 hkhkhk 7997 ljlj 4567r

[c_losed]

/* STRTOK.C: In this program, a loop uses strtok
* to print all the tokens (separated by commas
* or blanks) in the string named "string".
*/

#include <string.h>
#include <stdio.h>

char string[] = "begin hkhkhk 7997 ljlj 4567r end";
char seps[]   = " ";
char *token;

void main( void )
{
	printf( "%s\n\nTokens:\n", string );
	/* Establish string and get the first token: */
	token = strtok( string, seps );
	while( token != NULL )
	{
		/* While there are tokens in "string" */
		printf( " %s\n", token );
		/* Get next token: */
		token = strtok( NULL, seps );
	}
}

[c_losed]

begin和end 自己过滤下就ok了

[tianma2005123]

正则表达式，字符串匹配。

[ryfdizuo]

C++下为什么不用istringstream

#include <sstream>
char s[]="begin hkhkhk 7997 ljlj 4567r end";
istringstream istr( string(s) );
string section;
while( istr >> section )
{
  cout << section;
}

[ningto.com]

q结束输入

#include <iostream>
#include <string>
#include <vector>
using namespace std;

int _tmain(int argc, _TCHAR* argv[])
{

	vector<string> vs;
	string str;

	while (cin >> str)
	{
		if (str == "q")
		{
			break;
		}
		vs.push_back(str);
	}

	for (vector<string>::iterator iter = vs.begin() + 1; iter != vs.end() - 1; ++iter)
	{
		cout << *iter << " ";
	}

	system("pause");
	return 0;
}

[mibbadman]

[Quote=引用 4 楼 dizuo 的回复:]
C++下为什么不用istringstream

C/C++ code
#include <sstream>
char s[]="begin hkhkhk 7997 ljlj 4567r end";
istringstream istr( string(s) );
string section;
while( istr >> section )
{
cout << sectio……
[/Quote]++

[至善者善之敌]

#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>
#include <ITERATOR>

#define INPUT_STRING "begin hkhkhk 7997 ljlj 4567r end"

typedef std::vector<std::string> strvec;

int _tmain(int argc, _TCHAR* argv[])
{
	using namespace std;

	istringstream iss(INPUT_STRING);
	strvec strList;
	string strTemp;

	while(iss >> strTemp)
	{
		strList.push_back(strTemp);
	}

	//vector<std::string>::iterator iter=strList.begin();
	strList.erase(std::find(strList.begin(), strList.end(), "begin"));
	strList.erase(std::find(strList.begin(), strList.end(), "end"));
	// out put the result
	copy(strList.begin(), strList.end(), ostream_iterator<string>(cout, "\n"));

	return 0;
}

[你妹的特盗不]

	WCHAR buf[]=L"begin ss tt gg bbada rwas a aea d eqwrcx end";
	TRACE(L"%.*s\n",_countof(buf)-sizeof("begin ")-sizeof("end"),(buf+sizeof("begin ")));//mfc调试的,直接把trace改成print就可以了

[luchangxing09]

如果这个字符串很大怎么办呀，可能有几千个？如上述的方法就行不通

[你妹的特盗不]

[Quote=引用 9 楼 luchangxing09 的回复:]
如果这个字符串很大怎么办呀，可能有几千个？如上述的方法就行不通
[/Quote]

怎么行不通,随便多大都行得通..
"begin " "end" 只有这么长,再长的字符串,都能得到长度