合并列值
--*******************************************************************************************
表结构，数据如下：
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到结果：
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即：group by id, 求 value 的和（字符串相加）
1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
（所影响的行数为 2 行）
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb
/*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(2 行受影响)
*/
--SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id
/*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc
(2 row(s) affected)
*/
drop table tb
/*
标题：分拆列值1
作者：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间：2008-11-20
地点：广东深圳
描述
有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
*/
--1. 旧的解决方法(sql server 2000)
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b
SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','
DROP TABLE #
--2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)B
DROP TABLE tb
/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
(5 行受影响)
*/
--分拆列值
--原著：邹建
--改编：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-12-16 广东深圳
/*
有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
*/
--欲按id,分拆value列, 分拆后结果如下:
/*
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
*/
--1. 旧的解决方法(sql server 2000)
select top 8000 id = identity(int, 1, 1) into # from syscolumns a, syscolumns b
select A.id, substring(A.[values], B.id, charindex(',', A.[values] + ',', B.id) - B.id)
from tb A, # B
where substring(',' + A.[values], B.id, 1) = ','
drop table #
--2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
select A.id, B.value
from(
select id, [value] = convert(xml,' <root> <v>' + replace([value], ',', ' </v> <v>') + ' </v> </root>') from tb
)A
outer apply(
select value = N.v.value('.', 'varchar(100)') from A.[value].nodes('/root/v') N(v)
)B
drop table tb
/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
(5 行受影响)
*/
/*
select N'☞'
*/
/*
表1数据如下：
1 111,112
2 221,222,223
3 331,332,333,334
4 441,442
5 551,552,553,554
......
表2数据如下：
1 112,113
2 222,223,224
3 332,333,335,336
4 441,442
5 551,552,553,554
*/
create table t1(id int,val varchar(400))
insert into t1
select 1 ,'111,112' union all
select 2 ,'221,222,223' union all
select 3 ,'331,332,333,334' union all
select 4 ,'441,442' union all
select 5 ,'551,552,553,554'
go
create table t2(id int,val varchar(400))
insert into t2
select 1 ,'112,113' union all
select 2 ,'222,223,224' union all
select 3 ,'332,333,335,336' union all
select 4 ,'441,442' union all
select 5 ,'551,552,553,554'
go
with ct1 as
(
select distinct a.id,substring(a.val,b.number,charindex(',',a.val+',',b.number)-b.number) val
from t1 a,master..spt_values b
where b.[type] = 'p' and b.number between 1 and len(a.val)
and substring(','+a.val,b.number,1) = ','
),ct2 as
(
select distinct a.id,substring(a.val,b.number,charindex(',',a.val+',',b.number)-b.number) val
from t2 a,master..spt_values b
where b.[type] = 'p' and b.number between 1 and len(a.val)
and substring(','+a.val,b.number,1) = ','
),ct3 as
(
select id,val from ct1
union
select id,val from ct2
)
select id,stuff((select ','+val from ct3 where id = t.id for xml path('')),1,1,'') val
from ct3 t
group by id
drop table t1,t2
/**************
id val
----------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
1 111,112,113
2 221,222,223,224
3 331,332,333,334,335,336
4 441,442
5 551,552,553,554
(5 行受影响)
