STL中问题（问题就是程序注释部分）

[哈哈王戈多]

#include <algorithm>
#include <iostream>
#include <stdlib.h>
#include <vector>
#include <time.h>
#include <list>
#include <numeric>
#include <functional>
using namespace std;

#define SIZE 10
vector<int> vint(SIZE);
void main()
{
for(int i=0;i<10;i++)
vint.push_back(i+1);
copy(vint.begin(),vint.end(),ostream_iterator<int>(cout,"\t"));

}
问题描述：程序输出结果为：
0 0 0 0 0 0 0 0 0 0 //请问是怎么来的？？不明白！
1 2 3 4 5 6 7 8 9 10

[hahayezhe112]

vector<int> vint(SIZE);

[bdmh]

http://blog.csdn.net/xxxluozhen/article/details/5050550

[luciferisnotsatan]

vector<int> vint(SIZE);
初始化大小为10
vint.push_back(i+1);
这个push_back是在10个初始化的元素后继续追加，结果有20个元素了。

[yfk]

vector<int> vint(SIZE); // 构造函数，初始化为SIZE个元素
LZ可以：
cout << vint.size() << endl;
for(int i=0;i<10;i++)
vint.push_back(i+1);
cout << vint.size();

看下size

explicit vector ( size_type n, const T& value= T(), const Allocator& = Allocator() );
Constructs a vector container object, initializing its contents depending on the constructor version used:

explicit vector ( const Allocator& = Allocator() );
Default constructor: constructs an empty vector, with no content and a size of zero.
explicit vector ( size_type n, const T& value= T(), const Allocator& = Allocator() );
Repetitive sequence constructor: Initializes the vector with its content set to a repetition, n times, of copies of value.
template <class InputIterator> vector ( InputIterator first, InputIterator last, const Allocator& = Allocator() );
Iteration constructor: Iterates between first and last, setting a copy of each of the sequence of elements as the content of the container.
vector ( const vector<T,Allocator>& x );
Copy constructor: The vector is initialized to have the same contents (copies) and properties as vector x.

更多vector，参考：
http://blog.csdn.net/yfkiss/article/details/6537234