关于字符串截取的一个问题

[sparadise1003]

字符串有如下几种可能："3367B "或"3367B.1" 或 "3367B.1.1" 或 "3367B.1-1"大概这四种可能吧，我现在实现的功能是：如果有“.”就把第一个“.”之前的截取出来存为新字符串。

[金刚葫芦娃]

char *str,*str1;
strcpy(str,"3367B.1");
str1 = strtok(str,".");
结果:str1 = 3367B

[bdmh]

    string s = "abc.d";
	int i = s.find_first_of(".");
	string news = s.substr(0,i);

[赵4老师]

char s[]="3367B.1-1";
char t[20],*p;
strcpy(t,s);
p=strchr(t,'.');
if (p) *p=0;
printf("[%s]\n",t);

[ningto.com]

	int i = 0;
	while (arrDest[i])
	{
		if (arrDest[i] == '.')
		{
			arrDest[i] = '\0';
			break;
		}
		i++;
	}

[ningto.com]

#include <iostream>
using namespace std;

int _tmain(int argc, _TCHAR* argv[])
{
	char arrDest[] = "3367B.1.1";

	int i = 0;
	while (arrDest[i])
	{
		if (arrDest[i] == '.')
		{
			arrDest[i] = '\0';
			break;
		}
		i++;
	}
	cout << arrDest << endl;

	return 0;
}