python 三位数组 如何读取一列

[liuxialong]

我想在三位数组中读取出特定的column，形成一个一维数组。使用list实现，如何读取？

例如：
list = [[['a','b','c'],['d','f','g']],[['h','i','j'],['k','l','m']]]

list是一个三围数组

我要求读出'b' 'f' 'i' 'l'
用下标操作符如何实现？

用list[:][:][1]可以吗？

[hndcwynui]

>>> lst
[[['a', 'b', 'c'], ['d', 'f', 'g']], [['h', 'i', 'j'], ['k', 'l', 'm']]]
>>> lst[:][0][0][1]
'b'
>>> lst[:][0][1][1]
'f'
>>> lst[:][1][0][1]
'i'
>>> lst[:][1][1][1]
'l'

[I_NBFA]

mylist = [[['a','b','c'],['d','f','g']],[['h','i','j'],['k','l','m']]];
res = [mylist[i][j][1] for i in range(len(mylist)) for j in range(len(mylist[i]))];
print(res);

[liuxialong]

不可以直接用 m[:][:][1]吗？

[Quote=引用 2 楼 i_nbfa 的回复:]
Python code

mylist = [[['a','b','c'],['d','f','g']],[['h','i','j'],['k','l','m']]];
res = [mylist[i][j][1] for i in range(len(mylist)) for j in range(len(mylist[i]))];
print(res);
[/Quote]

[notax]

>>> l = [[['a','b','c'],['d','f','g']],[['h','i','j'],['k','l','m']]]
>>> sum(sum(l,[]),[])[1::3]
['b', 'f', 'i', 'l']
>>> 
>>> 
>>> l = [[['a','b','c'],['d','f','g']],[['h','i','j'],['k','l','m']]]
>>> l = reduce(lambda x, y: x+y, l)
>>> reduce(lambda x, y: x+y, l)[1::3]
['b', 'f', 'i', 'l']
>>> 

[notax]

>>> import itertools
>>> l = [[['a','b','c'],['d','f','g']],[['h','i','j'],['k','l','m']]]
>>> [i[1] for i in itertools.chain(*l)]
['b', 'f', 'i', 'l']

[notax]

>>> l = [[['a','b','c'],['d','f','g']],[['h','i','j'],['k','l','m']]]
>>> [i[1] for i in reduce(lambda x, y: x.extend(y) or x, l)]
['b', 'f', 'i', 'l']

[kesunhit]

zip(*l)[1]