求解：java.lang.IndexOutOfBoundsException: Index: 1, Size: 1

[乳臭未干]

我用Hibernate查询：
hql = "select u.email, u.password from ApplicantPO as u where u.username=?";
query = sessionH.createQuery(hql);
query.setString(0, Username);

list.clear();
list = query.list();
System.out.println("list.size() = " + list.size());

if(list.size()>0){
this.setEmail(list.get(0).toString().trim()); //给email赋值
System.out.println("查到的email为："+list.get(0).toString().trim());
this.setUserPassword(list.get(1).toString().trim()); //给userPassword赋值
}
HibernateServiceProvider.closeSession();

得到的是这样的结果：
list.size() = 1
查到的email为：[Ljava.lang.Object;@13cebda
2011-7-26 21:32:36 org.apache.catalina.core.StandardWrapperValve invoke
严重: Servlet.service() for servlet default threw exception
java.lang.IndexOutOfBoundsException: Index: 1, Size: 1
at java.util.ArrayList.RangeCheck(ArrayList.java:547)
at java.util.ArrayList.get(ArrayList.java:322)
at rims.action.GetPasswordAction.checkUser(GetPasswordAction.java:133)
at rims.action.GetPasswordAction.validate(GetPasswordAction.java:153)
at com.opensymphony.xwork2.interceptor.DefaultWorkflowInterceptor.doIntercept(DefaultWorkflowInterceptor.java:200)
at com.opensymphony.xwork2.interceptor.MethodFilterInterceptor.intercept(MethodFilterInterceptor.java:86)
at com.opensymphony.xwork2.DefaultActionInvocation$2.doProfiling(DefaultActionInvocation.java:224)

麻烦大家指点一二~

[龙四]

list.get(0).toString().trim()

[贪睡的兔子]

数组越界吧

[乳臭未干]

这句我有写啊~~
[Quote=引用 1 楼 ticmy 的回复:]

list.get(0).toString().trim()
[/Quote]

[乳臭未干]

唉~自己解决了：
if(list.size()>0){
ApplicantPO apo = (ApplicantPO)list.get(0);
System.out.println("查到的email为："+apo.getEmail());
System.out.println("查到的password为："+apo.getPassword());
}

需要返回一个对象~下面的 应该懂了吧~