HttpURLConnection的问题 高分求助

[zjt0318]

我想得到输入一个网址后，跳转后的网址，用HttpURLConnection该怎么做，求助！
这是我的代码：麻烦大家看看，兄弟我先谢谢！！！！！！！！！


HttpURLConnection httpurlconnection = null;
URL url = null;
url = new URL("一个网址url“);

httpurlconnection = (HttpURLConnection) url.openConnection();
httpurlconnection.setDoOutput(true);
httpurlconnection.setRequestMethod("POST");
httpurlconnection.setConnectTimeout(6*1000); //设置连接超时


String urlsting=httpurlconnection.getURL().toString();

我个人认为左后一句不对，怎么等到网页跳转后得到跳转后的网址呢！
我不想用webview控件，那样不想一个应用程序，我想放到后台运行！thanks

[zjt0318]

不好意思，打错字了，最后一句代码不对........大家见谅啊

[zjt0318]

求android高手当老师，我会认真跟着学习的》

[forqzy]

分析那个收到的 EntityUtils.toString(response.getEntity())， 就可以找到你要的东西

private String getDocuments(String url) {
String httpUrl = url;
HttpGet request = new HttpGet(httpUrl);
HttpClient httpClient = new DefaultHttpClient();
try {
HttpResponse response = httpClient.execute(request);
if (response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
String str = EntityUtils.toString(response.getEntity());

//
return str;
} else {
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return "";

}

[AspireHouse]

一般跳转后的地址都是在服务器返回的头字段location里面
HttpURLConnection httpurlconnection = null;
URL url = null;
url = new URL("一个网址url“);

httpurlconnection = (HttpURLConnection) url.openConnection();
httpurlconnection.setDoOutput(true);
httpurlconnection.setRequestMethod("POST");
httpurlconnection.setConnectTimeout(6*1000); //设置连接超时
responseCode = conn.getResponseCode();
switch (responseCode)
{
case HttpStatus.SC_MOVED_TEMPORARILY://302跳转 当然也可能是301、303、307
String urlsting = conn.getHeaderField("location");//这里也可能是相对路径，需要自己拼接
break;
default：
break;
}

[guoying_]

自己报个班吧，要找老师的话