jquery怎么修改xml里面的值高手请进......................

[dongdgh]

/*************************xml内容*************************/

<?xml version="1.0" encoding="utf-8"?>
<config>
<files name="filses" >
<key Text="啊啊啊" name="Deed" value=""></key>
<key Text="棒棒棒" name="Short" value=""></key>
<key Text="踩踩踩" name="Stamp" value=""></key>
<key Text="大大的" name="Mortgage" value=""></key>
</files>
</config>

/*********************Jquery内容*********************************/


$.ajax({
url: "1.xml",
dataType: "xml",
type: "get",
success: function (xml) {

//想进行对根据name来进行对value值的修改
},error: function (xml) {
alert("找不到1.xml文件!");
}

});

[子夜__]

jquery 操作XML

[dongdgh]

读取字节我是知道读取但是我不知道怎么修改哈!

[子夜__]

下载jquery.xmlext.js

$.getScript("jquery.xmlext.js", function() {
            var xd = $.parseXml("<items><center /></items>");
            var x = $(xd);
            x.find("center").appendXml("<bottom />").prependXml("<top />");
            x.find("top,bottom").afterXml("<After />").beforeXml("<Before />");
            alert(x.xml());
            var obj = { Name: "Darkthread", Score: 100 };
            xd = $.toXml(obj, "Person");
            alert($(xd).xml());
            xd = $.toXml(obj, "Person", true);
            alert($(xd).xml());
});

[huangwenquan123]

jq不能修改xml

   <script type="text/javascript" src="js/jquery-1.3.2.min.js"></script>
    <script type="text/javascript">
        $(document).ready(function(){
            $.ajax({
                url:"Handler.ashx",
                type:"get",
                data:"name=filses",
                success:function(result){
                    alert(result);
                }
            })
        })
    </script>

[huangwenquan123]

Handler.ashx

    public void ProcessRequest(HttpContext context)
    {
        context.Response.ContentType = "text/plain";
        if (!string.IsNullOrEmpty(context.Request.QueryString["name"]))
        {
            string name = context.Request.QueryString["name"];
            System.Xml.XmlDocument xml = new System.Xml.XmlDocument();
            xml.Load(context.Server.MapPath("1.xml"));
            System.Xml.XmlNodeList list = xml.SelectNodes("//files[@name='" + name + "']/key");
            foreach (System.Xml.XmlNode n in list)
                n.Attributes["value"].Value = "1";
            xml.Save(context.Server.MapPath("1.xml"));
            context.Response.Write("true");
            context.Response.End();
        }
    }