27,579
社区成员
发帖
与我相关
我的任务
分享
--示例数据
CREATE TABLE tb(Name varchar(10),Score decimal(10,2))
INSERT tb SELECT 'aa',99
UNION ALL SELECT 'bb',56
UNION ALL SELECT 'cc',56
UNION ALL SELECT 'dd',77
UNION ALL SELECT 'ee',78
UNION ALL SELECT 'ff',76
UNION ALL SELECT 'gg',78
UNION ALL SELECT 'ff',50
GO
--1. 名次生成方式1,Score重复时合并名次
SELECT *,Place=(SELECT COUNT(DISTINCT Score) FROM tb WHERE Score>=a.Score)
FROM tb a
ORDER BY Place
/*--结果
Name Score Place
---------------- ----------------- -----------
aa 99.00 1
ee 78.00 2
gg 78.00 2
dd 77.00 3
ff 76.00 4
bb 56.00 5
cc 56.00 5
ff 50.00 6
--*/
--2. 名次生成方式2,Score重复时保留名次空缺
SELECT *,Place=(SELECT COUNT(Score) FROM tb WHERE Score>a.Score)+1
FROM tb a
ORDER BY Place
/*--结果
Name Score Place
--------------- ----------------- -----------
aa 99.00 1
ee 78.00 2
gg 78.00 2
dd 77.00 4
ff 76.00 5
bb 56.00 6
cc 56.00 6
ff 50.00 8
--*/
select 姓名,分数
,名次= identity(int,1,1) into #1 from tab a
order by 分数,姓名
select * from #1
select 姓名,分数
,名次= (select count(*) from tab where 分数 <= a.分数)
from tab a
order by 分数
select 姓名,分数,row_number() over (order by 分数) as 名次
from tab
order by 分数