帮我看看atof()

[Microsues]

#include<iostream>
using namespace std;

double my_atof(const char* s)
{
	bool dot = true;
	double result = 0;
	int sign = 1;
	int i = 0;
	double temp = 1;
	for( ; isspace(s[i]) ;++i);
	sign = (s[i] == '-') ? -1 : 1;

	if(s[i] == '+' || s[i] == '-')
		++i;

	for( ; isdigit(s[i]) || s[i] == '.'; ++i){
		if(s[i] == '.'){
			dot = false;
			++i;
		}
		if(dot == true){
			result = result * 10 + (s[i] - '0');
		}
		else{
			temp = temp * 10;
			result = result + (s[i] - '0')/temp;
		}
	}

	return sign * result;
}


int main()
{
	cout<<my_atof(" 33990.09822")<<endl;
	return 0;
}

打印33990.1
怎么改进 输出33990.09822？

[healer_kx]

挺好的。

[至善者善之敌]

int main()
{
	cout<<setiosflags(ios::fixed)<<setiosflags(ios::showpoint)<<setprecision(5);//小数点后面的个数
		cout<< setw(8)<<my_atof("33990.09822")<<endl;
	return 0;
	//cout<<setiosflags()
}

[至善者善之敌]

忘了说记得加#include<iomanip>

[healer_kx]

[Quote=引用 3 楼 babilife 的回复:]

忘了说记得加#include<iomanip>
[/Quote]
+1

[赵4老师]

摒弃cout；使用printf！
#include <stdio.h>
//...
printf("%lg\n",my_atof(" 33990.09822"));