【求助】使用jaxb如何序列化 List对象啊

[程静涛]

List<Book> books =new ArrayList<Book>();
Book book=new Book();
book.setName="书名1";
book.setContent="内容1";

Book book2=new Book();
book2.setName="书名2";
book2.setContent="内容2";
books.add(book);
books.add(book2);

请问使用jaxb 如何实现 list 和xml之间的相互转化？？
非常感谢

[程静涛]

brightyq :
谢谢。
这种方法应该是很灵活的。转换列表的时候，依靠自主定制附加节点，是这个思想吧。反序列化的时候是要读取节点分析，放在list对象中么？

[程静涛]

huntor：
Thanks,
我已经是用了该方法。
虽然引入了一个类，但是使用起来确实很方便，将原有的列表序列化，转换为统一的object序列化，这样的话，只需要在原有的ArrayList上封装成为我们的List对象就可以和 基本的object的序列化统一了。使用很方便

[程静涛]

求助。。。。

[brightyq]

book类

private String name;
	private String content;

	public String getName() {
		return name;
	}

	public void setName(String name) {
		this.name = name;
	}

	public String getContent() {
		return content;
	}

	public void setContent(String content) {
		this.content = content;
	}

生成xml

List<Book> books =new ArrayList<Book>();
		Book book=new Book();
		book.setName("书名1");
		book.setContent("内容1");

		Book book2=new Book();
		book2.setName("书名2");
		book2.setContent("内容2");
		books.add(book);
		books.add(book2);
		
		JAXBContext context = JAXBContext.newInstance(Book.class);
		
		Marshaller marshaller = context.createMarshaller();
		marshaller.setProperty(Marshaller.JAXB_ENCODING, "GBK");
		marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, false);
		marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);

		String ns = "book";
		XMLOutputFactory output = XMLOutputFactory.newInstance();
		output.setProperty(XMLOutputFactory.IS_REPAIRING_NAMESPACES, true);
		
		
		File file = new File("d:/jaxbtest.txt");
		OutputStream out = new FileOutputStream(file);
		XMLStreamWriter writer = output.createXMLStreamWriter(out,"UTF-8");
		writer.writeStartDocument();
		writer.setDefaultNamespace(ns);
		writer.writeStartElement(ns,"booklist");
		
		int i = 0;

		for(Iterator it = books.iterator();it.hasNext();){
			QName qname = new QName("book" + String.valueOf(i));
			i++;
			Book bk = (Book)it.next();
			JAXBElement<Book> bookElement = new JAXBElement<Book>(qname,Book.class,bk);
			marshaller.marshal(bookElement, writer);
			writer.flush();
		}
		writer.writeEndElement();
		writer.writeEndDocument();
		writer.flush();

生成结果如下：
<?xml version='1.0' encoding='UTF-8'?>
<booklist xmlns="book">
<book0 xmlns="">
<content>内容1</content>
<name>书名1</name>
</book0>
<book1 xmlns="">
<content>内容2</content>
<name>书名2</name>
</book1>
</booklist>

[huntor]

Book.java

@XmlType(propOrder={"name","content"})
@XmlRootElement(name="book")
public class Book {
    private String name;
    private String content;

    @XmlElement
    public final String getContent() {
        return content;
    }

    public final void setContent(final String content) {
        this.content = content;
    }

    @XmlElement
    public final String getName() {
        return name;
    }

    public final void setName(final String name) {
        this.name = name;
    }
}

BookList.java

@XmlRootElement(name="booklist")
public class BookList {
    @XmlElement(name="book")
    private List<Book> booklist;

    public BookList(){
        booklist = new ArrayList<>();
    }

    public void add(Book book){
        booklist.add(book);
    }

    public Iterator<Book> iterator(){
        return booklist.iterator();
    }
}

            BookList books =new BookList();
            Book book=new Book();
            book.setName("书名1");
            book.setContent("内容1");

            Book book2=new Book();
            book2.setName("书名2");
            book2.setContent("内容2");
            books.add(book);
            books.add(book2);

            JAXBContext context = JAXBContext.newInstance(BookList.class);

            Marshaller marshaller = context.createMarshaller();
            marshaller.setProperty(Marshaller.JAXB_ENCODING, "UTF-8");
            marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
            marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);
            File file = new File("booklist.xml");
            marshaller.marshal(books,file);
            marshaller.marshal(books,System.out);

<booklist>
    <book>
        <name>书名1</name>
        <content>内容1</content>
    </book>
    <book>
        <name>书名2</name>
        <content>内容2</content>
    </book>
</booklist>

[liufrom1989]

有更好的方法，XmlElementWrapper和XMLElement配合使用

[liufrom1989]

@XmlElementWrapper(name="friends")
	@XmlElement(name = "friend")
	public List<UserBean> getFriends() {
		return friends;
	}

	public void setFriends(List<UserBean> friends) {
		this.friends = friends;
	}

[duxjin]

楼主在吗? 有xml 转为 javabean集合的 例子吗? 求看一下

[duxjin]

<?xml version="1.0" ?> <booklist xmlns="book"> <book0 xmlns=""><age>22</age><name>陆旭</name><stuNo>11</stuNo></book0> <book1 xmlns=""><age>33</age><name>大神</name><stuNo>33</stuNo></book1> </booklist> 有没有将上面xml ,用 jaxb 转为 list<student>,求解答哦!!!

[影子里的句号]

<?xml version="1.0" ?>
<booklist xmlns="book">
<book0 xmlns=""><age>22</age><name>陆旭</name><stuNo>11</stuNo></book0>
<book1 xmlns=""><age>33</age><name>大神</name><stuNo>33</stuNo></book1>
</booklist>