字符串中的空格转义

[iceblue22]

String a = "hello world baby";
请问如何将空格转义成转义字符，结果是a = "hello\u0000world\u0000baby"

[shixitong]

截取字符串判断，如果是空格则替换成空格的转义字符，最后拼接字符串

[iceblue22]

String a = "aaaaa aa";
char[] b = a.toCharArray();
for(int i = 0; i < b.length; i ++){
if("".equals(b[i])){
b[i]='\u0000';
}
System.out.println(b[i]);
}
System.out.println(b.toString());
这样写有错吗？怎么打印输出错误

[剑神一笑]

a = a.replaceAll("\\s","\u0000")

[iCielo]

其实就是HTML的编码和解码咯

javascript HTMLencode实现：
function HTMLEncode(strHTML)
{
var div = document.createElement('div');
div.innerText = strHTML;
return div.innerHTML;
}
javascript HTMLdecode实现：
function HTMLDecode(strEncodeHTML)
{
var div = document.createElement('div');
div.innerHTML = strEncodeHTML;
return div.innerText;
}

[niuniu20008]

[Quote=引用 2 楼 iceblue22 的回复:]
String a = "aaaaa aa";
char[] b = a.toCharArray();
for(int i = 0; i < b.length; i ++){
if("".equals(b[i])){
b[i]='\u0000';
}
System.out.println(b[i]);
}
System.out.println(b.toString());
这样写有……
[/Quote]
没有错误
b.toString()打印的[C@a90653,这不是错误
不考虑内存情况下面这种写法就可以

public class Test {

	public static void main(String[] args) {
		String a = "aaaaa aa";
		char[] b = a.toCharArray();
		String str = "";
		for (int i = 0; i < b.length; i++) {
			String s = ""+b[i];
			if (" ".equals(s)) {
				str = str + "\\u0000";
				continue;
			}
			str = str+b[i];
		}
		System.out.println(str);
	}
}

比较好的写法是这样

public class Test {

	public static void main(String[] args) {
		String a = "aaaaa aa";
		char[] b = a.toCharArray();
		StringBuilder sb = new StringBuilder("");
		for (int i = 0; i < b.length; i++) {
			String s = ""+b[i];
			if (" ".equals(s)) {
				sb.append("\\u0000");
				continue;
			}
			sb.append(b[i]);
		}
		System.out.println(sb.toString());
	}
}