如何用正则表达式截取字符串

[qq251833440]

有这么一段字符串:
[aaa]bbb
想分别截取字符串aaa(即中括号里面的字符)和bbb(即括号外面的字符),怎样写正则才能实现?
$str1=aaa
$str2=bbb


答案是这个
$str = '[aaa]bbb';
preg_match('/^\[(.*)\](.*)$/', $str, $matches);

$matches[1] == 'aaa';
$matches[2] == 'bbb';

怎么改写成C#代码

[qq251833440]

在线等！

[porschev]

        string str = "[aaa]bbb";
       
        Regex re = new Regex("^\\[(.*)\\](.*)$", RegexOptions.None);
        MatchCollection mc = re.Matches(str);
        foreach (Match ma in mc)
        {
            //ma.Groups[1].Value    结果：aaa
            //ma.Groups[2].Value;   结果：bbb
        }

[人生难得一只鸡]

 string tempStr = "[aaa]bbb";
            string pattern = @"\[([\s\S]*)\]([\s\S]*)";
            Regex re = new Regex(pattern);
            string str1 = Regex.Replace(tempStr,pattern,"$1");
            string str2 = Regex.Replace(tempStr, pattern, "$2");

[huangwenquan123]

            string str = "[aaa]bbb";
            Regex reg = new Regex(@"\[([^\]]+)\](.*)");
            Console.WriteLine(reg.Match(str).Groups[1].Value);
            Console.WriteLine(reg.Match(str).Groups[2].Value);

[haojuntu]

  string s = "[aaa]bbb";
            Regex regex=new Regex("\\[(?<a>\\w+)\\](?<b>\\w+)",RegexOptions.IgnoreCase);
          
            string a = string.Empty;
            string b = string.Empty;
            Match m = regex.Match(s);
            if (m.Success)
            {
                a = m.Groups["a"].ToString();
                b = m.Groups["b"].ToString();
            }