I'm trying to receive some data as json from a php file, the php seems to be good and the <em>html</em> too, but te jquery file doesn't do the .done function and I can't find why.
The Jquery version that I use is 3.1.0, and I'm using bootstrap for styles but I think it isn't important.
The HTML file:
<!DOCTYPE <em>html</em>>
<<em>html</em>>
<head>
<meta charset="utf-8">
<title>Registro Chat</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css" integrity="sha384-ggOyR0iXCbMQv3Xipma34MD+dH/1fQ784/j6cY/iJTQUOhcWr7x9JvoRxT2MZw1T" crossorigin="anonymous">
</head>
<body>
<h1>Chat 2.0</h1>
<div class="container col-md- mt-4">
<form id="formulario">
<div class="form-group">
<label for="usuario">Nombre de Usuario</label>
<input type="text" class="form-control" id="usuario" aria-describedby="emailHelp" placeholder="Introduzca el nombre de usuario">
<p id="p-usuario"></p>
</div>
<div class="form-group">
<label for="email">Email</label>
<input type="text" class="form-control" id="email" aria-describedby="emailHelp" placeholder="Introduzca su email">
<p id="p-email"></p>
</div>
<div class="form-group">
<label for="contra1">Contraseña</label>
<input type="password" class="form-control" id="contra1" aria-describedby="emailHelp" placeholder="Introduzca una contraseña">
<p id="p-contra1"></p>
</div>
<div class="form-group">
<label for="contra2">Repita la Contraseña</label>
<input type="password" class="form-control" id="contra2" placeholder="Repita su contraseña">
<p id="p-contra2"></p>
</div>
<button type="submit" class="btn btn-success bg-success">Enviar</button>
<a href="principal.<em>html</em>"><button type="button" class="btn btn-success bg-success">Inicio de Sesión</button></a>
</form>
</div>
<script src="//code.jquery.com/jquery-3.1.0.min.js"></script>
<script src="accionregistro.js"></script>
</body>
</<em>html</em>>
The JQuery file:
$(document).ready(principal);
function principal(){
$('#formulario').submit(runAjax);
}
function runAjax(event){
var enviados = {
'usuario' : $('#usuario').val(),
'email' : $('#email').val(),
'contra1' : $('#contra1').val(),
'contra2' : $('#contra2').val()
};
$.<em>ajax</em>({
type : 'POST',
url : 'backendregistro.php',
data : enviados,
dataType : 'json',
encode : true
})
.done(function(datos){
alert();
if(datos.exito){
alert();
$('0#p-usuario').text(datos.mensaje);
}else{
if(datos.error.vacio){
alert(datos.error.vacio);
//$('#p-usuario').text(datos.error.vacio);
}
if(datos.error.usuario){
$('#p-usuario').text(datos.error.usuario);
}
if(datos.error.email){
$('#p-email').text(datos.error.email);
}
if(datos.error.notmatch){
$('#p-contraseña1').text(datos.error.notmatch);
}
}
});
event.preventDefault();
}
PHP file:
<?php
$error=array();
$datos=array();
if(empty($_POST['usuario'])||empty($_POST['contra1'])||empty($_POST['contra2'])||empty($_POST['email'])){
$error['vacio']="No puede haber campos en blanco";
}else{
echo
$usuario = $_POST['usuario'].
$email = $_POST['email'].
$contraseña1 = $_POST['contra1'].
$contraseña2 = $_POST['contra2'];
}
//definimos la conexion a la base de datos
$mysqli = new mysqli('localhost','chat','chat2019','chat');
//comprobamos si el email ya existe
$mysqli -> query("select * from users where email='".$email."'");
if($mysqli->affected_rows!=0&&!empty($email)){
$error['email']="Ese email ya está registrado";
}
//comprobamos que no exista el usuario
$mysqli->query("select * from users where user='".$usuario."'");
if($mysqli->affected_rows!=0 && !empty($usuario)){
$error['usuario']="Ya existe ese nombre de usuario";
}
//si no hay errores hacemos el insert
if(empty($error)){
$datos['exito']=true;
$datos['mensaje']="Usuario registrado correctamente";
$mysqli->query("insert into users values ('".$usuario."','".$contraseña1."','".$email."')");
}else{
$datos['exito']=false;
$datos['error']=$error;
}
echo json_encode($datos);
?>
When I try to see in the console if every thing is going well, it seems that the json is being sent but then the done function doesn't work. I'm soo noob at web programing, I know that probably the way I'm doing is very unsecure, but I only want to know why it doesn't works, thanks you.
<em>使用</em>Ajax进行用户名动态校验，局部刷新<em>页面</em>1.在HTML<em>页面</em><em>中</em><em>使用</em>js脚本将请求数据发送给后台servlet
由按钮触发事件
查询
由js脚本对将数据发送到后台
var req = new XMLHttpRequest();
function queryInfos() {
I have some problem with the returned value of <em>ajax</em>.
this is the <em>ajax</em> code:
$(document).ready(function() {
var request;
$("#flog").submit(function(event) {
if(request)
request.abort();
event.preventDefault();
var form = $(this);
var serializedData = form.serialize();
var btnname = $('#log').attr('name');
var btnval = $('#log').val();
var btn = '&'+btnname+'='+btnval;
serializedData += btn;
request = $.<em>ajax</em>({
type: form.attr('method'),
url: form.attr('action'),
data: serializedData,
});
request.done(function(data, status, jdXHR) {
alert(data);
});
request.fail(function(jdXHR, status, error) {
});
});
});
it takes data from a form and send it to another page.
this is the second page:
<?php include 'head.php'; ?>
<?php
if($_POST['login']) {
session_regenerate_id(true);
$con = mysqli_connect("localhost", "Alessandro", "ciao", "freetime")
or die('Could not connect: ' . mysqli_error($con));
$query = 'SELECT * FROM users WHERE username="' . $_POST['user'] . '"';
$result = mysqli_query($con, $query) or die('Query failed: ' . mysqli_error($con));
if(mysqli_num_rows($result) == 0) {
mysqli_close($con);
session_unset();
session_destroy();
$res = false;
return $res;
}
$query = 'SELECT password FROM users WHERE username="' . $_POST['user'] . '"';
$result = mysqli_query($con, $query) or die('Query failed: ' . mysqli_error($con));
$line = mysqli_fetch_array($result, MYSQL_ASSOC);
if(md5($_POST['password']) != $line['password']) {
mysqli_close($con);
session_unset();
session_destroy();
return false;
}
?>
<?php include 'foot.php'; ?>
and in .done the returned data is all the <em>html</em> page.
How can I retrieve only a data, like $res? I tried with json_encode() but with no results.
If in the second page I delete the lines include 'head.php' and include 'foot.php' it works. But I need that the secon page is <em>html</em>, too.
Somenone can help me?
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