Create Table Test (Val int)
insert into test (val) values (1) --1-4
insert into test (val) values (2)
insert into test (val) values (3)
insert into test (val) values (4)
insert into test (val) values (7) --7-9
insert into test (val) values (8)
insert into test (val) values (9)
insert into test (val) values (15) --15-16
insert into test (val) values (16)
Select * from test
--查出连续数据的最小值
select val from test a
where not exists
(select top 1 val from test b where b.val = a.val-1)
--查出连续数据的最大值
select val from test a
where not exists
(select top 1 val from test b where b.val = a.val+1)
declare @t table(num int)
insert into @t
select 1
union all
select 2
union all
select 3
union all
select 4
union all
select 5
union all
select 12
union all
select 17
union all
select 18
union all
select 19
union all
select 20
union all
select 25
select
rtrim(a.num) as col,(case when min(b.num)!=a.num then rtrim(min(b.num)) else '' end) as col2
from
(select t.num from @t t where not exists(select 1 from @t where num=t.num-1)) a,
(select t.num from @t t where not exists(select 1 from @t where num=t.num+1)) b
where
a.num <=b.num
group by
a.num
/*------------ ------------
1 5
12
17 20
25
(4 行受影响)*/
declare @t table(num int)
insert into @t
select 1
union all
select 2
union all
select 3
union all
select 4
union all
select 5
union all
select 12
union all
select 17
union all
select 18
union all
select 19
union all
select 20
union all
select 25
;with cte as (
select *,ROW_NUMBER () over (order by num) as id from @t a
where not exists (
select 1 from @t
where num = a.num - 1
)
), cte1 as (
select *,ROW_NUMBER () over (order by num) as id from @t a
where not exists (
select 1 from @t
where num = a.num + 1
)
)
select cte.num ,cte1.num from cte ,cte1
where cte.id = cte1.id
--结果
num num
1 5
12 12
17 20
25 25
Create Table Test (Val int)
insert into test (val) values (1) --1-4
insert into test (val) values (2)
insert into test (val) values (3)
insert into test (val) values (4)
insert into test (val) values (7) --7-9
insert into test (val) values (8)
insert into test (val) values (9)
insert into test (val) values (15) --15-16
insert into test (val) values (16)
go
;with cte as(
select val,val as val1 from test a where not exists(select 1 from test where val=a.val-1)
union all
select a.val,b.val from cte a inner join test b on a.val1=b.val-1
)select val,max(val1)val1 from cte group by val
/*
val val1
----------- -----------
1 4
7 9
15 16
(3 行受影响)
*/
go
drop table test
Create Table # (id int identity(1,1),Val int)
insert into # (val) values (1) --1-4
insert into # (val) values (2)
insert into # (val) values (3)
insert into # (val) values (4)
insert into # (val) values (7) --7-9
insert into # (val) values (8)
insert into # (val) values (9)
insert into # (val) values (15) --15-16
insert into # (val) values (16)
select ltrim(min(val))+'-'+ltrim(max(val))
from
(
Select *,val-id v from # a
)a
group by v
/*
-------------------------
1-4
7-9
15-16
(3 row(s) affected)
*/
declare @t table(num int)
insert into @t
select 1
union all
select 2
union all
select 3
union all
select 4
union all
select 5
union all
select 12
union all
select 17
union all
select 18
union all
select 19
union all
select 20
union all
select 25
select min(num)start,
max(num)[end]
from
(select num ,num-row_number()over(order by num)as grp
from @t)as D
group by grp
/*
start end
----------- -----------
1 5
12 12
17 20
25 25
*/
declare @t table(num int)
insert into @t
select 1
union all
select 2
union all
select 3
union all
select 4
union all
select 5
union all
select 12
union all
select 17
union all
select 18
union all
select 19
union all
select 20
union all
select 25
select IDENTITY(int,1,1) as id,* into #t from @t
select
min(num)start,
max(num)[end]
from
(select num ,num-id as grp from #t)as D group by grp
drop table #t
/*start end
----------- -----------
1 5
12 12
17 20
25 25
(4 行受影响)
*/
Create Table Test (Val int)
insert into test (val) values (1) --1-4
insert into test (val) values (2)
insert into test (val) values (3)
insert into test (val) values (4)
insert into test (val) values (7) --7-9
insert into test (val) values (8)
insert into test (val) values (9)
insert into test (val) values (15) --15-16
insert into test (val) values (16)
select identity(int,1,1) rn, a.val into #s
from Test a
left join Test b on a.val-1=b.val
where b.val is null
select identity(int,1,1) rn, a.val into #e
from Test a
left join Test b on a.val=b.val-1
where b.val is null
select #s.val '开始',#e.val '结束'
from #s
inner join #e on #s.rn=#e.rn
开始 结束
----------- -----------
1 4
7 9
15 16
