请教一个增长率的SQL，谢谢

[520NET]

SELECT T.FEE_MONTH,
T.MI_CODE,
SUM(NVL(T.AMNT, 0)) AMNT, /*费用*/
SUM(NVL(T.TIMES, 0)) TIMES, /*人次*/
SUM(NVL(T.PCOUNT, 0)) PCOUNT /*人数*/
FROM M_ZF_INSTFEE_MSTAT T
WHERE T.PSNTYPE = '1' /*城镇居民*/
AND T.FEE_MONTH BETWEEN '201012' AND '201112'
AND (T.MI_CODE = '00000004' OR T.MI_CODE = '05110004')
GROUP BY T.MI_CODE, T.FEE_MONTH
显示结果如下：
FEE_MONTH MI_CODE AMNT TIMES PCOUNT
1 201012 00000004 0 0 0
2 201012 05110004 0 0 0
3 201101 00000004 20326 5 5
4 201101 05110004 3328 1 1
5 201102 00000004 2503 2 2
6 201102 05110004 0 0 0
7 201103 00000004 3672 1 1
8 201103 05110004 0 0 0
9 201104 00000004 0 0 0
10 201104 05110004 0 0 0
11 201105 00000004 0 0 0
12 201105 05110004 0 0 0
我想得到如下结果，请教SQL，谢谢！
FEE_MONTH MI_CODE AMNT TIMES PCOUNT PRE_AMNT（上一月份的金额）
1 201012 00000004 0 0 0 0
2 201012 05110004 0 0 0 0
3 201101 00000004 20326 5 5 0
4 201101 05110004 3328 1 1 0
5 201102 00000004 2503 2 2 20326
6 201102 05110004 0 0 0 3328
7 201103 00000004 3672 1 1 2503
8 201103 05110004 0 0 0 0
9 201104 00000004 0 0 0 3672
10 201104 05110004 0 0 0 0
11 201105 00000004 0 0 0 0
12 201105 05110004 0 0 0 0

[opps_zhou]

求上一个月用 lag(金额字段) over(order by 日期字段)

[opps_zhou]

给你写一个简单的示例

with tbl as
(
    select '201101' as sdate, '001' as id, 11 as price from dual
     union all
    select '201101' as sdate, '002' as id, 12 as price from dual
     union all
    select '201102' as sdate, '001' as id, 21 as price from dual
     union all
    select '201102' as sdate, '002' as id, 22 as price from dual
)
select sdate, id, price, nvl(lag(price) over(partition by id order by sdate), 0) as last_price
  from tbl
 order by sdate, id;


SDATE  ID       PRICE LAST_PRICE
------ --- ---------- ----------
201101 001         11          0
201101 002         12          0
201102 001         21         11
201102 002         22         12

[funfenffun]

[Quote=引用 2 楼 opps_zhou 的回复:]

给你写一个简单的示例

SQL code

with tbl as
(
select '201101' as sdate, '001' as id, 11 as price from dual
union all
select '201101' as sdate, '002' as id, 12 as price from dual
union all
……
[/Quote]

那岂不是说我要输出100条记录，那我就要在tb1中写100条select语句了，这肯定不行

[opps_zhou]

[Quote=引用 3 楼 funfenffun 的回复:]

引用 2 楼 opps_zhou 的回复:

给你写一个简单的示例

SQL code

with tbl as
(
select '201101' as sdate, '001' as id, 11 as price from dual
union all
select '201101' as sdate, '002' as id, 12 as price from dua……
[/Quote]

你先弄清楚 with 的用法是干嘛的先

[funfenffun]

好吧，我看花掉了，您老只是建了一个例子的临时表，没睡醒的说