关于“sin()”函数

[zyg_23]

怎样使用SIN（）函数求角度。请用代码说明，加以说明 Thinks

[icy_csdn]

SIN函数是用来求某一角度的正弦值的，不是用来根据正弦值求角度的。

[Jarky]

求反函数吧！先包含一个＃include "math.h"
直接用asin(x)；-<x<1

[karma]

assume X is (-1,1), try

Atn(X / Sqr(-X * X + 1)) * 180/3.1415926

[Bardo]

Secant Sec(X) = 1 / Cos(X)
Cosecant Cosec(X) = 1 / Sin(X)
Cotangent Cotan(X) = 1 / Tan(X)
Inverse Sine Arcsin(X) = Atn(X / Sqr(-X * X + 1))
Inverse Cosine Arccos(X) = Atn(-X / Sqr(-X * X + 1)) + 2 * Atn(1)
Inverse Secant Arcsec(X) = 2 * Atn(1) – Atn(Sgn(X) / Sqr(X * X – 1))
Inverse Cosecant Arccosec(X) = Atn(Sgn(X) / Sqr(X * X – 1))
Inverse Cotangent Arccotan(X) = 2 * Atn(1) - Atn(X)
Hyperbolic Sine HSin(X) = (Exp(X) – Exp(-X)) / 2
Hyperbolic Cosine HCos(X) = (Exp(X) + Exp(-X)) / 2
Hyperbolic Tangent HTan(X) = (Exp(X) – Exp(-X)) / (Exp(X) + Exp(-X))
Hyperbolic Secant HSec(X) = 2 / (Exp(X) + Exp(-X))
Hyperbolic Cosecant HCosec(X) = 2 / (Exp(X) – Exp(-X))
Hyperbolic Cotangent HCotan(X) = (Exp(X) + Exp(-X)) / (Exp(X) – Exp(-X))
Inverse Hyperbolic Sine HArcsin(X) = Log(X + Sqr(X * X + 1))
Inverse Hyperbolic Cosine HArccos(X) = Log(X + Sqr(X * X – 1))
Inverse Hyperbolic Tangent HArctan(X) = Log((1 + X) / (1 – X)) / 2
Inverse Hyperbolic Secant HArcsec(X) = Log((Sqr(-X * X + 1) + 1) / X)
Inverse Hyperbolic Cosecant HArccosec(X) = Log((Sgn(X) * Sqr(X * X + 1) + 1) / X)
Inverse Hyperbolic Cotangent HArccotan(X) = Log((X + 1) / (X – 1)) / 2
Logarithm to base N LogN(X) = Log(X) / Log(N)

From MSDN (VB)