如何达到这个效果？

[kevinjay567]

35 AAA
47 AAA
51 AAA
36 BBB
35 BBB
47 BBB
……
===>

AAA 35,47,51
BBB 36,35,47
……
求大侠帮助，谢谢。

[快溜]

合并列值 
--*******************************************************************************************
表结构，数据如下： 
id    value 
----- ------ 
1    aa 
1    bb 
2    aaa 
2    bbb 
2    ccc 

需要得到结果： 
id    values 
------ ----------- 
1      aa,bb 
2      aaa,bbb,ccc 
即：group by id, 求 value 的和（字符串相加） 

1. 旧的解决方法(在sql server 2000中只能用函数解决。) 
--=============================================================================
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 
--1. 创建处理函数 
CREATE FUNCTION dbo.f_strUnite(@id int) 
RETURNS varchar(8000) 
AS 
BEGIN 
    DECLARE @str varchar(8000) 
    SET @str = '' 
    SELECT @str = @str + ',' + value FROM tb WHERE id=@id 
    RETURN STUFF(@str, 1, 1, '') 
END 
GO 
-- 调用函数 
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id 
drop table tb 
drop function dbo.f_strUnite 
go
/* 
id          value      
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 
（所影响的行数为 2 行） 
*/ 
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 
-- 查询处理 
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( 
        SELECT [values]= STUFF(REPLACE(REPLACE( 
            ( 
                SELECT value FROM tb N 
                WHERE id = A.id 
                FOR XML AUTO 
            ), ' <N value="', ','), '"/>', ''), 1, 1, '') 
)N 
drop table tb 

/* 
id          values 
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 

(2 行受影响) 
*/ 

--SQL2005中的方法2 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 

select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') 
from tb 
group by id 

/* 
id          values 
----------- -------------------- 
1          aa,bb 
2          aaa,bbb,ccc 

(2 row(s) affected) 

*/ 

[中国风]

select 
COl1,
col2=stuff((select ','+col2 from t1 where COl1=a.COl1 for xml path('')),1,1,'')
from t1 as a
group by col1

[-晴天]

create table tb(c1 int,c2 varchar(10))
insert into tb select 35,'AAA'
insert into tb select 47,'AAA'   
insert into tb select 51,'AAA'   
insert into tb select 36,'BBB'
insert into tb select 35,'BBB'  
insert into tb select 47,'BBB'
go
select c2,stuff((select ','+LTRIM(c1) from tb where c2=a.c2 for xml path('')),1,1,'')c1 from tb a group by c2
/*
c2         c1
---------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
AAA        35,47,51
BBB        36,35,47

(2 行受影响)

*/
go
drop table tb

[中国风]

use Tempdb
go
--> --> 
 
declare @T table([Col2] int,[Col1] nvarchar(3))
Insert @T
select 35,N'AAA' union all
select 47,N'AAA' union all
select 51,N'AAA' union all
select 36,N'BBB' union all
select 35,N'BBB' union all
select 47,N'BBB'
 
select 
COl1,
col2=stuff((select ','+RTRIM(col2) from @T where COl1=a.COl1 for xml path('')),1,1,'')
from @T as a
group by col1
/*
COl1	col2
AAA	35,47,51
BBB	36,35,47*/

[--小F--]

----------------------------------------------------------------
-- Author  :fredrickhu(小F，向高手学习)
-- Date    :2011-11-03 14:43:24
-- Version:
--      Microsoft SQL Server 2008 R2 (RTM) - 10.50.1617.0 (Intel X86) 
--	Apr 22 2011 11:57:00 
--	Copyright (c) Microsoft Corporation
--	Enterprise Evaluation Edition on Windows NT 6.1 <X64> (Build 7600: ) (WOW64)
--
----------------------------------------------------------------
--> 测试数据：[tb]
if object_id('[tb]') is not null drop table [tb]
go 
create table [tb]([co11] int,[col2] varchar(3))
insert [tb]
select 35,'AAA' union all
select 47,'AAA' union all
select 51,'AAA' union all
select 36,'BBB' union all
select 35,'BBB' union all
select 47,'BBB'
--------------开始查询--------------------------
select
 [col1]=stuff((select ','+ltrim([co11]) from tb  where col2=t.col2 for xml path('')), 1, 1, '') ,col2
from
 tb t
group by
 col2 
----------------结果----------------------------
/* col1                                                                                                                                                                                                                                                             col2
---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- ----
35,47,51                                                                                                                                                                                                                                                         AAA
36,35,47                                                                                                                                                                                                                                                         BBB

(2 行受影响)

*/

[kevinjay567]

都是高手啊