怎么通过注解方式来访问Action?

[iswsc]

import org.springframework.stereotype.Controller;

@Controller("/list")//如何能访问到这个Action?
public class LogisticsTpyeAction extends Action {
....
}

struts-config.xml

          <form-beans>
		<form-bean name="logisticstypeform" type="com.wsc.web.formbean.LogisticsTypeForm"/>
	</form-beans>
         <action path="/list" >
	    <forward name="list" path="/WEB-INF/logistics/list.jsp"/>
	</action>

我这么写为什么访问不到Action？

[iswsc]

来个人，帮帮忙啊！！！

[明悟]

struts-config.xml

<package name="default"  extends="struts-default">
        <!-- Generic Tags start-->
		<action name="logisticstypeform" class="com.wsc.web.formbean.LogisticsTypeForm">
			<result name="SUCCESS">/WEB-INF/logistics/list.jsp</result>
		</action>
		<!-- Generic Tags end-->	
    </package>

import org.springframework.stereotype.Controller;

@Controller("/list")//如何能访问到这个Action?
public class LogisticsTpyeAction extends Action {
....
return "SUCCESS";
}

[iswsc]

<form-beans>
    <form-bean name="producttypeform" type="com.wsc.web.formbean.product.ProductTypeForm"/>
    </form-beans>
<action-mappings> 
<action path="/list" name="productTypeForm" scope="request">
    <forward name="list" path="/WEB-INF/page/product/producttypelist.jsp" />
</action>
</action-mappings> 

import org.springframework.stereotype.Controller;
@Controller("/list")
public class ProductTypeAction extends Action {
    ...
    return mapping.findForward("list");
}

我的是这样的，访问list.do就报 HTTP Status 500 - No action instance for path /list could be created

[beiouwolf]

注解配置不需要在xml里做什么
需要引用convertion那个包
默认会载入以Action结尾的,并继承ActionSupport
而且你这个是struts1?struts1有注解方案的吗?

[hllfl]

http://www.cnblogs.com/wayne_wang/archive/2011/01/24/1942927.html
1有注解么

[iswsc]

我这个是看视频做的？里面的老师说就是这样做的，他能访问到list.do我就进不去，

[iswsc]

这个是Spring的注解