python 数据存放

[hukui161]

1.xr = [['a',1], ['a', 2], ['b', 3], ['b',4],['c',5]]
2.xr = [['a',1], ['b', 2], ['c', 3], ['d',4],['e',5]]
3.xr = [['a',1], ['a',2], ['b', 3], ['c',4], ['c',5']]
4.xr = [['a', 1]]

将xr中的数据存放到两个[]中
xr 在为1时存放为 res1 = [1,3, 5], res2= [2,4]
xr 在为2时存放为 res1 = [1,2,3,4,5] res2 = []
xr 在为3时存放为 res1 = [1, 3, 4] res2 = [2, 5]
xr 在为4时存放为 res1 = [1] res2 = []

这个用python怎么实现了？

[hukui161]

没人回啊？

[WaistCoat07]

没看懂问题

[WaistCoat07]

xr = [['a',1], ['a', 2], ['b', 3], ['b',4],['c',5]]
# xr=[['a',1], ['b', 2], ['c', 3], ['d',4],['e',5]]
# xr=[['a',1], ['a',2], ['b', 3], ['c',4], ['c',5']]
# xr=[['a', 1]]
res1 = []
res2 = []
temp = []

for item in xr:
	if item[0] in temp:
		res2.append(item[1])
	else:
		res1.append(item[1])
		temp.append(item[0])

[hukui161]

这样好像不行了。XR 存放的数据可能有上面四种情况。

[hukui161]

def GetNum():
global  g_InactiveNumber
global  g_ActiveNumber
g_InactiveNumber = []
    if(xr[0] == xr[-1]):
        g_ActiveNumber.append(xr[0][1])
        return
    lastNum = 0
    lastModuleID = 0
    for tmpList in xr:
        if(lastModuleID == 0):
            lastModuleID = tmpList[0]
            lastNum  = tmpList[1]
        elif(lastModuleID == tmpList[0]):
            if(lastSlotNum not in g_ActiveNumber):
                g_ActiveNumber.append(lastNum)
            if(tmpList[1] not in g_InactiveNumber):
                g_InactiveNumber.append(tmpList[1])
            
        elif(lastModuleID != tmpList[0]):
            if(lastSlotNum not in g_InactiveNumber or lastNum not in g_ActiveNumber):
                g_ActiveNumber.append(lastSlotNum)
                g_ActiveNumber.append(tmpList[1])
            else:
                g_ActiveNumber.append(tmpList[1])
            lastModuleID = tmpList[0]
            lastNum =  tmpList[1]

[WaistCoat07]

def func(data):
    temp = []
    res1 = []
    res2 = []
    for item in data:
        if item[0] in temp:
            res2.append(item[1])
        else:
            res1.append(item[1])
            temp.append(item[0])
    return (res1, res2)

def main():
    xr = [['a',1], ['a', 2], ['b', 3], ['b',4],['c',5]]
    print(func(xr))

[hukui161]

你可能没看懂意思。就是XR的数据有几种类型，当xr中有[['a',1], ['a', 2]]的时候，当有两个'a'出现的时候 将第一个出现的 ['a',1] 中的1加入res中，将['a', 2] 中的2加入到res2中。
当只有一个['c',5]时， 将5加入到 res1中。

[WaistCoat07]

你可以试下我的代码，完全符合你的要求。

[hukui161]

好像是可以。