请教SQLite数据库读写BLOB字段。

[dangdang2471]

假设表如下，现需要将照片d:\1.jpg添加到库中，请问该如何做？
CREATE TABLE test(username varchar(20),password varchar(20), img blob)

最好给出详细的代码。
谢谢大家！

[dangdang2471]

补充：照片大小大于8KB

[dangdang2471]

问题已解决，多谢！

// 连接字符串 data source=d:\test.db3;password=1234
                SQLiteConnectionStringBuilder connStr = new SQLiteConnectionStringBuilder();
                connStr.DataSource = @"d:\test.db3";
                connStr.Password = "1234";
                conn = new SQLiteConnection(connStr.ToString());
                conn.Open();

                // 插入数据
                string SQL = "INSERT INTO test(k) VALUES(:k)";
                SQLiteCommand cmd = conn.CreateCommand();
                cmd.CommandText = SQL;

                // 取图标，准备插入到数据库BLOB字段
                FileStream picStream = File.OpenRead(@"d:\1.bmp");
                byte[] bArray = new byte[picStream.Length];
                picStream.Read(bArray, 0, bArray.Length);
                picStream.Close();

                cmd.Parameters.Add("k", DbType.Binary).Value = bArray;  // BLOB
                cmd.ExecuteNonQuery();

                //取出数据  
                cmd.CommandText = "SELECT k FROM test";
                System.Data.SQLite.SQLiteDataReader reader = cmd.ExecuteReader();
                while (reader.Read())
                {
                    MemoryStream streamImage = new MemoryStream(reader["k"] as byte[]);
                    pictureBox1.Image = Image.FromStream(streamImage);
                    streamImage.Close(); // 关闭流
                }
                reader.close();

                conn.close();

[sdl2005lyx]

SQLite没用过，需要使用参数化方式：给你一个例子：

        FileStream fs = new FileStream(@"c:\test.jpg", FileMode.Open, FileAccess.Read);
        BinaryReader br = new BinaryReader(fs);

        img = Image.FromFile(@"c:\test.jpg");
        MemoryStream ms = new MemoryStream();
        img.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg);

        byte[] myData = ms.ToArray();

        SqlConnection cn = new SqlConnection("Data Source=(local);Initial Catalog=utscadadb;Integrated Security=SSPI; User Id=sa;Password=ut2001;");
        SqlCommand cmd = new SqlCommand("Update Table1 Set data = (@data) where id =3", cn);
        cmd.Parameters.Add("@file ", SqlDbType.VarChar).Value = "d:\\test.jpg";
        cmd.Parameters.Add("@data ", SqlDbType.Image).Value = myData;

        cn.Open();
        cmd.ExecuteNonQuery();
        cn.Close();