sql 拼字符串

肥龙上天 2011-11-24 10:42:09

表结构如下
create table #t(id varchar(50),msg varchar(800))
insert #t
select 'a','职位1'
union all
select 'a','职位2'
union all
select 'a','职位3'
union all
select 'b','职位1'
union all
select 'b','职位2'

想获得如下的结构
id1 msg
a '职位1,职位2,职位3'
b '职位1,职位2'
...全文
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肥龙上天 2011-11-24
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thanks All
结单!
勿勿 2011-11-24
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必须要查到msg的值和id批对。一次是查不出来的。
[Quote=引用 10 楼 yangsnow_rain_wind 的回复:]
一次查询获得,
如:
select id,stuff((select ','+msg from #t where id=t1.id for xml path('')),1,1,'') from #t t1 group by id
就相当于查了两次表#t
问下能对表查询一次就得出结果吗?
[/Quote]
pengxuan 2011-11-24
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[Quote=引用 10 楼 yangsnow_rain_wind 的回复:]
一次查询获得,
如:
select id,stuff((select ','+msg from #t where id=t1.id for xml path('')),1,1,'') from #t t1 group by id
就相当于查了两次表#t
问下能对表查询一次就得出结果吗?
[/Quote]
肥龙上天 2011-11-24
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一次查询获得,
如:
select id,stuff((select ','+msg from #t where id=t1.id for xml path('')),1,1,'') from #t t1 group by id
就相当于查了两次表#t
问下能对表查询一次就得出结果吗?
pengxuan 2011-11-24
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你们有没有明明提交回复了,可贴子就是没有,还得再回复一次
pengxuan 2011-11-24
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select id,stuff((select ','+msg from #t where id=t1.id for xml path('')),1,1,'') from #t t1 group by id
/*
id
-------------------------------------------------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
a 职位1,职位2,职位3
b 职位1,职位2

(2 行受影响)

*/
AcHerat 元老 2011-11-24
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create table #t(id varchar(50),msg varchar(800))
insert #t
select 'a','职位1'
union all
select 'a','职位2'
union all
select 'a','职位3'
union all
select 'b','职位1'
union all
select 'b','职位2'

select id,
stuff((select ','+msg from #t where id = t.id for xml path('')),1,1,'') msg
from #t t
group by id

drop table #t

/**************

id msg
-------------------------------------------------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
a 职位1,职位2,职位3
b 职位1,职位2

(2 行受影响)
百年树人 2011-11-24
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select id,
msg=stuff((select ','+msg from #t where id=t.id for xml path('')),1,1,'')
from #t t
group by id
pengxuan 2011-11-24
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select id,stuff((select ','+msg from #t where id=t1.id for xml path('')),1,1,'') from #t t1 group by id
/*
id
-------------------------------------------------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
a 职位1,职位2,职位3
b 职位1,职位2

(2 行受影响)
*/
--小F-- 2011-11-24
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/****************************************************************************************************************************************************** 
合并分拆表数据

整理人:中国风(Roy)

日期:2008.06.06
******************************************************************************************************************************************************/

--> --> (Roy)生成測試數據

if not object_id('Tab') is null
drop table Tab
Go
Create table Tab([Col1] int,[Col2] nvarchar(1))
Insert Tab
select 1,N'a' union all
select 1,N'b' union all
select 1,N'c' union all
select 2,N'd' union all
select 2,N'e' union all
select 3,N'f'
Go

合并表:

SQL2000用函数:

go
if object_id('F_Str') is not null
drop function F_Str
go
create function F_Str(@Col1 int)
returns nvarchar(100)
as
begin
declare @S nvarchar(100)
select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1
return @S
end
go
Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab

go

SQL2005用XML:

方法1:

select
a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'')
from
(select distinct COl1 from Tab) a
Cross apply
(select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b

方法2:

select
a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44))
from
(select distinct COl1 from Tab) a
cross apply
(select Col2=(select COl2 from Tab where COl1=a.COl1 FOR XML AUTO, TYPE)
.query(' <Tab>
{for $i in /Tab[position() <last()]/@COl2 return concat(string($i),",")}
{concat("",string(/Tab[last()]/@COl2))}
</Tab>')
)b

SQL05用CTE:

;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab)
,Roy2 as
(select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1
union all
select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1)
select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0)


生成结果:
/*
Col1 COl2
----------- ------------
1 a,b,c
2 d,e
3 f

(3 行受影响)
*/


--参考
拆分表:

--> --> (Roy)生成測試數據

if not object_id('Tab') is null
drop table Tab
Go
Create table Tab([Col1] int,[COl2] nvarchar(5))
Insert Tab
select 1,N'a,b,c' union all
select 2,N'd,e' union all
select 3,N'f'
Go

--SQL2000用辅助表:
if object_id('Tempdb..#Num') is not null
drop table #Num
go
select top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns b
Select
a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID)
from
Tab a,#Num b
where
charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','
--2000不使用辅助表
Select
a.Col1,COl2=substring(a.Col2,b.number,charindex(',',a.Col2+',',b.number)-b.number)
from
Tab a join master..spt_values b
ON B.type='p' AND B.number BETWEEN 1 AND LEN(A.col2)
where
substring(','+a.COl2,b.number,1)=','


SQL2005用Xml:

select
a.COl1,b.Col2
from
(select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)a
outer apply
(select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))b




SQL05用CTE:

;with roy as
(select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tab
union all
select Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>''
)
select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)

生成结果:
/*
Col1 COl2
----------- -----
1 a
1 b
1 c
2 d
2 e
3 f
*/
AcHerat 元老 2011-11-24
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create table #t(id varchar(50),msg varchar(800))
insert #t
select 'a','职位1'
union all
select 'a','职位2'
union all
select 'a','职位3'
union all
select 'b','职位1'
union all
select 'b','职位2'

select id,
stuff((select ','+msg from #t where id = t.id for xml path('')),1,1,'') msg
from #t t
group by id
geniuswjt 2011-11-24
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05用xml,等楼下贴,LZ搜索合并列值
pengxuan 2011-11-24
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又见合并
苦苦的潜行者 2011-11-24
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好难哦!,学习了.

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