python webservice: from SOAPpy import WSDL
大漠山鹰 2011-11-25 11:52:04 我在用SOAPpy.WSDL 时也遇到了这个问题,希望高手路过时指点一下:
>>> from SOAPpy import WSDL
>>> url = "http://211.137.45.104:9006/LnXxtCpInterface/services/LNXxtSyncService?wsdl"
>>> server = WSDL.Proxy(url)
/usr/lib/pymodules/python2.6/SOAPpy/wstools/XMLSchema.py:2871: DeprecationWarning: object.__init__() takes no parameters
tuple.__init__(self, args)
>>> server = WSDL.Proxy(url)
>>> server.methods.keys()
[u'sendMo', u'syncResponseRpt', u'sendMt', u'syncStaff', u'syncCorp']
>>> server.methods['sendMt']
<SOAPpy.wstools.WSDLTools.SOAPCallInfo instance at 0xeb9ab8>
>>> server.methods['sendMt'].inparams
[<SOAPpy.wstools.WSDLTools.ParameterInfo instance at 0xeb9b00>]
>>> server.methods['sendMt'].inparams[0].type
(u'service.global.v1_0.wsdl.protocol.xxt', u'ArrayOf_soapenc_string')
>>> server.methods['sendMt'].inparams[0].name
u'mtInfo'
>>> server.methods['sendMt'].outparams[0].name
u'sendMtReturn'
>>> server.methods['sendMt'].outparams[0].type
(u'http://schemas.xmlsoap.org/soap/encoding/', u'string')
>>> server.sendMt(['a','b'])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/pymodules/python2.6/SOAPpy/Client.py", line 470, in __call__
return self.__r_call(*args, **kw)
File "/usr/lib/pymodules/python2.6/SOAPpy/Client.py", line 492, in __r_call
self.__hd, self.__ma)
File "/usr/lib/pymodules/python2.6/SOAPpy/Client.py", line 406, in __call
raise p
SOAPpy.Types.faultType: <Fault soapenv:Server.generalException: : <SOAPpy.Types.structType detail at 13700416>: {'fault': <SOAPpy.Types.structType multiRef at 13700272>: {'text': 'SoapHeader is null', 'messageId': 'SEV_0003'}, 'exceptionName': 'xxt.protocol.obj.v1_0.common.ServiceException', 'hostname': 'ln_xxt_mh01'}>
#NOTE:
我这里只是调用了一下 sendMt() 方法,输入参数在java 中 其实就是一个 String[] , 为什么在 这里会出现这样的错误?