字符串转换

[sandy1983]

int MakeFrame(char *PointNo,char *info)
{
	char pn1,pn2,pn3;
	int data2;
	pn1= ((PointNo[0]<<4)|PointNo[1]);
	pn2= ((PointNo[2]<<4)|PointNo[3]);
	pn3= ((PointNo[4]<<4)|PointNo[5]);

  	data2 = rand() * 20 / (double)RAND_MAX;
//	FE 01 01 06 67 C0 08 01 00 4B 12 00 A7 42 E6 1B 55 66 77 88 4A
	Fmt(info, "FE %d[w2p0] %d[w2p0] %d[w2p0] 67 C0 08 01 00 4B 12 00 A7 42 %d[w2p0] 00 55 66 77 88 4A",pn1,pn2,pn3,data2);
	strcat (info, "\0");
	return 0;	
}

char *PointNo="010106";
如何把“010106”格式化到char info[100]里，使第2,3,4字节成为01 01 06
例帧字符串：FE 01 01 06 67 C0 08 01 00 4B 12 00 A7 42 E6 1B 55 66 77 88 4A

[duke56]

可用sprintf()函数

[柯本]

给你个参考:

#include <stdio.h>
#include <stdlib.h>

int MakeFrame(char *PointNo,char *info)
{
    unsigned  int  pn1,pn2,pn3;
    int data2;

    sscanf(PointNo,"%2x%2x%2x", &pn1,&pn2,&pn3);
   
    data2 = rand() * 20 / (double)RAND_MAX; //这个不明白,data2永远为0
//    FE 01 01 06 67 C0 08 01 00 4B 12 00 A7 42 E6 1B 55 66 77 88 4A
    sprintf(info, "FE %02x %02x %02x 67 C0 08 01 00 4B 12 00 A7 42 %02x 00 55 66 77 88 4A",pn1 & 0xff,pn2 & 0xff ,pn3 & 0xff,data2);
    return 0;    
}
int main()
{

	  char buff[100];
	  MakeFrame("010106",buff);
	  printf("%s\n",buff);
}