请教linux 脚本操作

[ak_kay]

A目录：
20111210-13.txt
B目录：
...
20111210-11.txt
20111210-12.txt
20111210-13.txt
20111210-14.txt
20111210-15.txt
...
有什么方法通过A目录下的-13文档，匹配B目录20111210-13.txt，并打印及其以后的文档（即13,14,15...）出来；

说明，B目录文档可能不按以上例子顺序，不过最终结果都是（13,14,15...）

[askandstudy]

大概试了下好像可以，你试试看，不行再改改。

#!/bin/bash
for i in `ls /tmp/log`
do
#echo $i
ds=`ls /tmp`
ds2=`echo $ds|grep "$i"`
if [ "$ds2" != "" ]
then
#echo $ds2
echo $i ${ds#*$i}
fi
#${ds/*$i/$i} && echo $result || echo '' 
done

[askandstudy]

[root@RHEL6A shcode]# ls /tmp/A
20111210-13.txt
[root@RHEL6A shcode]# ls /tmp/B
20111210-11.txt  20111210-12.txt  20111210-13.txt  20111210-14.txt  20111210-15.txt
[root@RHEL6A shcode]# cat sh14.sh 
#!/bin/bash
dira='/tmp/A'
dirb='/tmp/B'
for i in `ls $dira`
do
	ds=`ls $dirb`
	ds2=`echo $ds|grep "$i"`
	if [ "$ds2" != "" ]
	then
		echo $i ${ds#*$i}
	fi
done

[root@RHEL6A shcode]# ./sh14.sh 
20111210-13.txt 20111210-14.txt 20111210-15.txt
[root@RHEL6A shcode]# 

[ljc007]

fileA=`ls ./a`
ls -1 ./b | sed -n "/$fileA/,\$p"

[askandstudy]

[Quote=引用 3 楼 ljc007 的回复:]

Assembly code
fileA=`ls ./a`
ls -1 ./b | sed -n "/$fileA/,\$p"
[/Quote]

学习了

[agustawestland]

sed -n "/$fileA/,\$p"

能否解释一下！！！